Answer / rajesh

we can solve this wid equations
let sachin = xy = 10*x + y
dravid = mn= 10*m + n
ganguly = nm = 10*n +m

nw 10*(x+m+n) + (y+m+n) = 240 ....(1)
since the unit place of the sum is zero

y+m+n must be multiple of 10
even if its 9+9+9 its 27 so it has to 10 or 20 probabilty
of 20 is more

y+m+n=20
substitute in (1)
we get x+m+n=22
therefore
x-y=2
nw the possible combination fr sachins score
is
31, 42, 53, 64, 75, 86, 97
use it 31 the total sum would be very less
approx. around middle value we get
sachin = 75
dravid = 87
ganguly = 78

Answer / venugopal

sachin-75
dravid-78
ganguly-87

dravid score=75+3
because sachin scored 75
7+5=12
1+2=3
ganguly scored is reverse of dravid
87
75+78+87=240

Answer / hemant joshi

.Sachin's score must be less than 86, otherwise Dravid's
score would be more than 99. Also, he must have scored
atleast 42 - incase Dravid and Ganguly scored 99 each.
Also, as none of them scored more than 99 and the total runs
scored by them is 240,their individual scores must be around 80.
Now use hit and trial method to solve the teaser...>>
ian its yup its 75,87,78.
sachin -75
dravid - 87
ganguly - 78

Answer / pst

both d ans above are right...but venu's seems 2 b more
interesting!

Answer / guest

Sachin, Dravid and Ganguly scored 75, 87 and 78 respectively.

Sachin's score must be less than 86, otherwise Dravid's
score would be more than 99. Also, he must have scored
atleast 42 - incase Dravid and Ganguly scored 99 each.

Also, as none of them scored more than 99 and the total runs
scored by them is 240; their individual scores must be
around 80.

Now, use trial-n-error method to solve the teaser.

Raj has a jewel chest containing Rings, Pins and Ear-rings. The chest contains 26 pieces. Raj has 2 1/2 times as many rings as pins, and the number of pairs of earrings is 4 less than the number of rings. How many earrings does Raj have?

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