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Mark ate half of a pizza on Monday. He ate half of what was
left on Tuesday and so on. He followed this pattern for one
week.
How much of the pizza would he have eaten during the week?
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Answer / guest
Mark would have ate 127/128 (99.22%) of the pizza during the
week.
Mark ate half the pizza on Monday. On Tuesday, he would have
ate half of the remaining pizza i.e. 1/4 of the original
pizza. Similarly, he would have ate 1/8 of the original
pizza on Wednesday and so on for the seven days.
Total pizza Mark ate during the week is
= 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128
= 127/128
= 99.22% of the original pizza
| Is This Answer Correct ? | 58 Yes | 4 No |
Answer / divya
Mark ate 1/2 of the pizza on 1st day, 1/2 left
1/4 on the second..., 1/4 left
.....................
.....................
on the 7th day, ate 1/128 and 1/128 is left.
so, he ate 1-(1/128) of the pizza
ie, 127/128
ie,99.22%.
| Is This Answer Correct ? | 21 Yes | 3 No |
Answer / pawan
Given, Ram ate half a cheese on Monday he ate half of what was left on Tuesday and so on.
Amount of cheese eaten by Ram =12+12×12+12×12×12……..+127
⇒ Amount of cheese eaten by Ram =12×1−1271−12
⇒ Amount of cheese eaten by Ram =12×1−112812=127128=0.9922
∴ Amount of cheese eaten by Ram in% = 99.22%
| Is This Answer Correct ? | 3 Yes | 2 No |
Answer / deepak gupta
7/16 is eat in a week and 9/16 is left in one week
| Is This Answer Correct ? | 1 Yes | 3 No |
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