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A mule and a donkey were carrying full sacks on their backs.
The mule started complaining that his load was too heavy.
The donkey said to him "Why are you complaining? If you gave
me one of your sacks I'd have double what you have and if I
give you one of my sacks we'd have an even amount."
How many sacks were each of them carrying? Give the minimal
possible answer.
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Answer / guest
The mule was carrying 5 sacks and the donkey was carrying 7
sacks.
Let's assume that the mule was carrying M sacks and the
donkey was carrying D sacks.
As the donkey told the mule, "If you gave me one of your
sacks I'd have double what you have."
D + 1 = 2 * (M-1)
D + 1 = 2M - 2
D = 2M - 3
The donkey also said, "If I give you one of my sacks we'd
have an even amount."
D - 1 = M + 1
D = M + 2
Comparing both the equations,
2M - 3 = M + 2
M = 5
Substituting M=5 in any of above equation, we get D=7
Hence, the mule was carrying 5 sacks and the donkey was
carrying 7 sacks.
| Is This Answer Correct ? | 41 Yes | 4 No |
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