how to take time as input in the format (12:02:13) from
user so that controls remains between these columns?
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find level of following tree (state, parent) " J,D I,D H,C E,B F,B G,C B,A D,A C,A A,& K,E L,E L,F M,F N,G O,H P,I P,H Q,I R,J S,K U,P T,L
Given a table of the form: Product Sold on A 1/1/1980 B 1/1/1980 C 1/1/1980 A 1/1/1980 B 1/1/1980 C 2/1/1980 A 2/1/1980 There are 30 products and 10,000 records of such type. Also the month period during which sales happened is given to u. Write the program to display the result as: Product Month No. of copies A January 12 A February 15 A March 27 B January 54 B February 15 B March 10 C January 37
Complexity T(n) What is the time complexity T(n) of the following portions of code? For simplicity, you may assume that n is a power of 2. That is, n = 2k for some positive integer k. a) ? for (i = 1; i <= n; i++) { j = n; cout << i << ? ? j << ? ? << endl; } b) ? for (i = 0; i <= n; i += 2) { j = n; cout << i << ? ? j << ? ? << endl; } c) ? for (i = n; i >= 1; i = i/2) { j = n; cout << i << ? ? j << ? ? << endl; } d) for (i = 1; i <= n; i++) { j = n; while (j >= 0) { cout << i << ? ? j << ? ? << endl; j = j - 2; } }
void main() { int i,j=2; for(i=0;i<3;i++) if(j=i) cout<<"Lotus "; else cout<<"Rose "; } Its result is Rose Lotus Lotus.. How? Explain it?
write a function that reverse the elements of an array in place.The function must accept only one pointer value and return void.
Find the maximum product of three numbers in an array? Eg. 9,5,1,2,3 Max product= 9*5*3= 135 The array can hav negative numbers also..
what is virtual constroctor ? give an exam for it?-(parimal dhimmar)
what is the diffrence between ++x , x++ pleaaaaase ???
. Write a program using two-dimensional arrays that computes the sum of data in tows and the sum of data in columns of the 3x3 (three by three) array variable n[3][3].
main(){int a=5,b 10,c=2, d;a=b c;d=++a=(--c)*2; printf("%d%d%d%d,a,b,c,d; return o;}
what is the use of using for loop as "for(;;)"?
U hv to enter a range from a and b and search hw many no. of times a pattern n. occurs between the range a and b. Eg :i/p:enter range :0 100 Enter pattern: 13 o/p: the no. times 13 occurred betwwn 0 to 100:1 Eg :i/p:enter range :100 1000 Enter pattern: 13 o/p: the no. times 13 occurred betwwn 100 to 1000: (in this 13,113,131,132,133…139,213,313,…913 all these will be counted)