struct ptr
{
int a;
char b;
int *p;
}abc;
what is d sizeof structure without using "sizeof" operator??
Answers were Sorted based on User's Feedback
Hi All,
The size of any data type is depends on the compiler
(including struct, union and enum). But the question does
not mean, "what is the size of the given structure".
It actually means,
Find the size of the structure without using sizeof()
operator.
The Answer, irrespective of compiler would be,
Output of the following code.
-First printf gives the size of the structure, wthout using
size of operator.
-U can cross check the ans using sizeof() operator in the
second printf().
#include<stdio.h>
struct name
{
int a;
char b;
int *p;
}abc;
main()
{
struct name *ptr, *ptr1;
ptr = &abc;
ptr1 = ptr + 1;
printf("WITHOUT USING sizeof() OPERATOR: %d \n",((char *)
ptr1 - (char *)ptr));
printf("USING sizeof() OPERATOR: %d \n", sizeof(abc));
getch();
}
Is This Answer Correct ? | 13 Yes | 0 No |
Answer / avinash dubey
the correct answer in gcc compiler is 12..
concept of structure padding is involved here..
Is This Answer Correct ? | 11 Yes | 2 No |
Answer / vishnu948923
void main()
{
int x,y;
y=&abc.a;
x=(&abc->p+1);
printf("%d",x-y);
}
Is This Answer Correct ? | 8 Yes | 5 No |
Answer / kk
12 is answer
int a takes 4 bytes
char b takes 4 bytes due to data padding
int *p any pointer takes 4 bytes
so totally 12 bytes........
Is This Answer Correct ? | 4 Yes | 1 No |
Answer / gagandeep
The total size would be 5.
Since 'int a' takes 2;
'char b' takes 1; and
'int *p' takes 2 (Note: Any pointer variable would take 2 bytes)
There is no additional size of 'struct' data structure.
Hence 5 is the value.
Is This Answer Correct ? | 12 Yes | 10 No |
In Linux, its 12 bytes.
int a ------- 4 bytes
char b ------- 1 byte.
but as the next element is integer, it wont fit in the
remaining 3 bytes left after the "char b" occupies the first byte of the 4 byte chunk. so these 3 bytes wont be used for storing "int *p". these will be padded. next 4 bytes will be used for storing *p.
to prove it.
int size;
size = (&(abc.p) + sizeof(abc.p)) - &abc.a ;
printf("size = %d",size);
Is This Answer Correct ? | 1 Yes | 0 No |
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