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Vipul was studying for his examinations and the lights went
off. It was around 1:00 AM. He lighted two uniform candles
of equal length but one thicker than the other. The thick
candle is supposed to last six hours and the thin one two
hours less. When he finally went to sleep, the thick candle
was twice as long as the thin one.
For how long did Vipul study in candle light?
- 13 Answers
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Answer / krishna kanth reddy
3 hours from 1A.M....That means upto early morning 4 A.M
| Is This Answer Correct ? | 58 Yes | 6 No |
Answer / rajesh
let the height of the candles be 4 ft
2 hr half of the thin candle lit now height 2 ft.
again 1 hr lit makes the thin candle 1 ft.
but the thick candle lasts 6 hr
in three hour it lits half of its height so 2 ft remaining
so the candles were lit three hours
till 4 am he used the candles
| Is This Answer Correct ? | 27 Yes | 1 No |
Answer / priyanshu gupta
let no. of hrs b x
it is given The thick candle is supposed to last six hours
and the thin one two hours less.
so 6-x=2(4-x)
6-x=8-2x
2x-x=8-6
x=2
so he studied 2 hrs in candle light.
| Is This Answer Correct ? | 18 Yes | 16 No |
Answer / sanjay sudheer
Both have the same length (i.e, say L in meters 'm')
Thick candle melting rate (L/6) of units m/hr
Thick candle melting rate (L/4) of units m/hr
Assume the time after which the given condition is satisfied (That is after 'h' hours)
[L- [(L/6)*h] ] = 2* [L- [(L/4)*h] Solve we will end up with 3hrs
h=3 hrs;
This is the condition for any variable length of the candle;
Try with candle lengths of for easy understanding (i.e., 4, 12, 24 etc) u will endup with same condition { thick candle is twice lengthy than the thin one}
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / vivek
IN response to above answer
What if we assume the height of the two candles to be 6 ft??
| Is This Answer Correct ? | 2 Yes | 3 No |
Answer / rohit solanki
Let both of their height be x.
For every hour thin will burn x/4 of x and thick will burn x/6 of x.
After 3 hrs remaining thin will be x - 3*x/4 = x/4 and
remaining thick will be x - 3*x/6 = x/2
Thus after 3 hrs thick will be twice of thin x/2 = 2(x/4)
hence solved.
| Is This Answer Correct ? | 0 Yes | 1 No |
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