void main()
{
for(int i=0;i<5;i++);
printf("%d",i);
}
What is the output?..
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Answer Posted / pramod
if it is in C it displays an error "indicating that "i"
cannot be declared in loop and i as undefined symbol"
if it the case of C++ it displays "5" because C++ supports
dynamic declaration and once declared anywhere in the
program(even in loops) can be used anytime in that program
| Is This Answer Correct ? | 2 Yes | 2 No |
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