Answer / ruchi

#include<stdio.h>
#include<conio.h>
int main()
{
int num,i,f=0,k=0,d,m;
printf("\n Enter the number ");
scanf("%d",&num);
m=num;
while(k<=m)
{
k=k+1;
f=0;
d=num%k;
if(d==0)
{
i=2;
while(i<=k-1)
{
if(k%i==0)
{
break;
}
i++;
}
if(i==k)
{
printf("\nPrime Factor %d ",k);
}
}
}
getch();
}

Answer / neha

#include<stdio.h>
#include<conio.h>
int main()
{
int num,i=1,j,k;
printf("\n\tEnter the number:");
scanf("%d",&num);
while(i<=num)
{
k=0;
if(num%i==0)
{
j=1;
while(j<=i)
{
if(i%j==0)
k++;
}
j++;
if(k==2)
printf("\n\t%d is a Prime factor:"i);
}
i++;
}
return 0;
}

What will the code below print when it is executed?   int x = 3, y = 4;         if (x = 4)                 y = 5;         else                 y = 2;         printf ("x=%d, y=%d ",x,y);

0 Answers  

---

why integer range between -327680to+32767

2 Answers  

---

In cryptography, you could often break the algorithm if you know what was the original (plain) text that was encoded into the current ciphertext. This is called the plain text attack. In this simple problem, we illustrate the plain text attack on a simple substitution cipher encryption, where you know each letter has been substituted with a different letter from the alphabet but you don’t know what that letter is. You are given the cipherText as the input string to the function getwordSets(). You know that a plain text "AMMUNITION" occurs somewhere in this cipher text. Now, you have to find out which sets of characters corresponds to the encrypted form of the "AMMUNITION". You can assume that the encryption follows simple substitution only. [Hint: You could use the pattern in the "AMMUNITION" like MM occurring twice together to identify this]

0 Answers   Infosys,

---

What is modeling?

0 Answers  

---

What is a void * in c?

0 Answers  

---

What is identifiers in c with examples?

0 Answers  

---

Write a program for deleting duplicate elements in an array

3 Answers   Subex,

---

What is a lookup table in c?

0 Answers  

---

what are far pointers?

1 Answers  

---

FILE *fp1,*fp2; fp1=fopen("one","w") fp2=fopen("one","w") fputc('A',fp1) fputc('B',fp2) fclose(fp1) fclose(fp2)} a.error b. c. d.

0 Answers   Wilco,

---

what is the difference b/w compiler and debugger?

2 Answers   Assurgent,

---

Write a routine that prints out a 2-D array in spiral order!

1 Answers   Lucent,

---