Interested to Buy Any Domain ? << Click Here >> for more details...
Consider a c++ template funtion
template<class T>
T& Add(T a, T b){return a+b ;}
if this function is called as
T c = Add("SAM", "SUNG");
what will happen? What is the problem in the template
declaration/ How to solve the problem.
- 7 Answers
- 17455 Views
- LG, Samsung, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / sg
"SAM" and "SUNG" will be considered as const char * and
there will be an compile time error. To over come this we
can call the fun as
string c = Add<string>("SAM","SUNG");
as the string class as '+' operator overloaded and it will
add the two string.
| Is This Answer Correct ? | 15 Yes | 1 No |
Answer / tathagata chakraborty
None of the other answers are coming to the point of this
question.They r all wrong.
right answer is the code will crash while returning frm Add
(). bcause the function is returning a local variable of
type T i.e. a+b as a refference. u cannont return a local
variable as refference bcause that will go out of scope as
soon as the function returns.
| Is This Answer Correct ? | 11 Yes | 3 No |
Answer / prasad
i will provide error.
declare template function as,
T Add(T a, T b){return a+b ;}
| Is This Answer Correct ? | 10 Yes | 4 No |
Answer / skc
The error is adding Two pointers isn't alowed in C/C++.
The compiler imlicitly treats "SAM" as const char*. We need
to write a function with "explicit" keyword declaration like
explicit char * Add (const char* x1, const char* x2)
{
// check for null pointers.
// allocate strlen(x1)+strlen(x2)+1 using malloc
// say char*a1 = malloc...;
// check if malloc returns null..take corrective actions
// strcpy (a1, x1);
// strcat (a1, x2);
//strcat (a1, '\0');
return a1; // ask the caller to free the memory allocated
// for a1
}
since this function is writen explicit the compiler will
invoke this function and not call the default template
function.
this is what appears to me. haven't coded and verified.
// Regards, SADIQ
| Is This Answer Correct ? | 4 Yes | 4 No |
Answer / pranay
MISTAKE:
1.returning a temp object so it goes out of scope.
2.using + for c-type strings.
SOLUTION:
string s = Add("SAM","SUNG");
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / mms zubeir
There are two things to be considered here.
First, T will be an unknown type in the place where we call
which gives a compilation error.
Second, if we call like this:
std::string c = Add("SAM", "SUNG"); or,
char* c = Add("SAM", "SUNG");
the compiler will convey an error since the arguments to
Add are interpretted as char pointers. The error may be
something like, "cannot add two pointers....".
| Is This Answer Correct ? | 4 Yes | 5 No |
Answer / sv
1) Compiler will throw the error as C++ doesnt support +
operator for string. Another point is T c = Add
("SAM","SUNG"), where the function call assign to a
TEMPLATE object type, it syntactical error.
2)We need to write a seperate add function as given below
char* Add( const char *s1, const char*s2);
This will solve the problem
| Is This Answer Correct ? | 3 Yes | 8 No |
What do you mean by delegate? Can a user retain delegates?
Write about the use of the virtual destructor?
How Virtual functions call up is maintained?
How const functions will be treated by compiler?
Mention the ways in which parameterized can be invoked. Give an example of each.
Why can templates only be implemented in the header file?
What is name mangling?
What is a protocol class?
Can a built-in function be recursive?
What is the history of c++?
What is the difference between multiple and multilevel inheritance in c++?
What is c++ programming language?
STL 
