Answer / arun

area of a rhomgus is 1/2 d1*d2; it's given d1+d2 = 12
(d1+d2)^2=d1^2 + d2^2 + 2*d1*d2
since diagonals are perpendicular to each other
(d1^2 + d2^2)/4 = 5^2 = 25

therefore, (d1+d2)^2 = 100 + 2d1d2;
which gives d1d2 = 22
so area = 11 cm sq

Answer / yesaswini

side of rhombus,a=5cm
diagonals=d1,d2
area,A=1/2(d1d2)
a^2=(d1^2+d2^2)/4=25
d1+d2=12
on squaring the above equation, we get
d1^2+d2^2+2(d1d2)=144
100+2(2A)=144
4A=44
A=11
area=11

Answer / vivek

11 sq cm

Answer / vikas chauhan

11 sq cm.

Answer / savitha

Area of the rhombus is 4 a square. so it is 100cm

Answer / salma

Area of rhombus when you know the length of the diagonals
is half the product of the diagonals

Therefore area=(d1d2)/2

where d1 is the length of the first diagonal whereas d2 is
the length of the other diagonal

sum of diagonals =12. so length of each is 6

area=(6*6)/2=36/2=18sq.cm

Answer / chinna

area of rhombus is 1/2d(l1+l2)
1/2*5*12=30sq.

Answer / krishna bagdi

72 cm sq.

Answer / devika gohel

18 cm

Answer / chinna

area of rhombus is 1/2d(l1+l2)
1/2*5*12=30sq.

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