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C program code
int zap(int n)
{
if(n<=1)then zap=1;
else zap=zap(n-3)+zap(n-1);
}
then the call zap(6) gives the values of zap
[a] 8 [b] 9 [c] 6 [d] 12 [e] 15
- 6 Answers
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Answer / gg
Error::invalid lvalue in assignment
for both the statements followed by IF & ELSE .
coz zap is a function name.And trying to assign a value.
if the Code is :
int zap(int n)
{
int zap1;
if(n<=1)
(zap1 = 1);
else
(zap1 = zap(n-3)+zap(n-1));
}
Ans Is :: 1
If the Code is :
int zap(int n)
{
int zap1;
if(n<=1)
return (zap1 = 1);
else
return (zap1 = zap(n-3)+zap(n-1));
}
Ans Is ::9
| Is This Answer Correct ? | 23 Yes | 4 No |
Answer / deepa
error there is no keyword as then ,therefore it will
treat 'then' as a variable which wud lead it to compilation
error
| Is This Answer Correct ? | 15 Yes | 8 No |
Answer / manishsoni
int zap(int n)
{
int a;
if(n<=1)
a=1;
else
a=zap(n-3)+zap(n-1);
return a;
}
main()
{
int result;
result=zap(6);
printf("%d",result);
getch();
}
it gives us 9;
Manish soni(MoNu)
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / madhu
if (n<=1)
zap = 1;
it gives a compile time error invlaid l value assignment.
zap is a function and cannot be assigned a value
| Is This Answer Correct ? | 1 Yes | 6 No |
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