A 12 address lines maps to the memory of

[a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none




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A 12 address lines maps to the memory of [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none ..

Answer / guest

b

Is This Answer Correct ?    43 Yes 14 No

A 12 address lines maps to the memory of [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none ..

Answer / prasanna hugar

1) 12 address is ma12 address is mapped to 2^12 = 4096 bits
2) 4096/8 = 512bytes( dividing by 8 because converting bits
to bytes 8 bits = 1 bytes)
3) 512/1024 = 0.5 K bytes

I think my answer is cleared your problem

Is This Answer Correct ?    25 Yes 0 No

A 12 address lines maps to the memory of [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none ..

Answer / indermohan singh

b. Because 2^12= 4Kbits=4/8Kbytes=0.5 Kbytes

Is This Answer Correct ?    19 Yes 5 No




A 12 address lines maps to the memory of [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none ..

Answer / eumine

Sorry i mistakenly wrote the answer [b] it is [d].

Is This Answer Correct ?    23 Yes 10 No

A 12 address lines maps to the memory of [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none ..

Answer / eumine

12 address lines can map to 4096 bytes of memory.
So Answer is [b].

Is This Answer Correct ?    23 Yes 16 No

A 12 address lines maps to the memory of [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none ..

Answer / ahmed eldesokey

12 address is mapped to 2^12 = 4096 byte
so
4096 byte / 1024 = 4 Kbyte

then the answer is [ d ] none it is mapped on 4 KB

Is This Answer Correct ?    17 Yes 10 No

A 12 address lines maps to the memory of [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none ..

Answer / saki

2^n bits n is no of address lines so 2^12=4096 bits
4096/8= 512 bits which is 0.5 k byte

Is This Answer Correct ?    4 Yes 0 No

A 12 address lines maps to the memory of [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none ..

Answer / divya

Here 2^12=4096 but it is in bit so need to convert it into byte so we do 4096/8=512=0.5k byte. so the answer is b)

Is This Answer Correct ?    0 Yes 0 No

A 12 address lines maps to the memory of [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none ..

Answer / singh

Since word size not given so assuming that at each location 1 bit lies... We get 12 address lines to map 4096 bits..i.e .5 Kbytes... !!

Is This Answer Correct ?    0 Yes 0 No

A 12 address lines maps to the memory of [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none ..

Answer / sravz

here why 4bytes is divided by 8bytes ? can you explain me clearly

Is This Answer Correct ?    1 Yes 4 No

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