Here 2^12=4096 but it is in bit so need to convert it into byte so we do 40

A 12 address lines maps to the memory of

[a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none

Question Posted / divya

Answer Posted / divya

Here 2^12=4096 but it is in bit so need to convert it into byte so we do 4096/8=512=0.5k byte. so the answer is b)

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