A 12 address lines maps to the memory of

[a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none




Answer Posted / prasanna hugar

1) 12 address is ma12 address is mapped to 2^12 = 4096 bits
2) 4096/8 = 512bytes( dividing by 8 because converting bits
to bytes 8 bits = 1 bytes)
3) 512/1024 = 0.5 K bytes

I think my answer is cleared your problem

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