What does $1 mean in bash?
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How will you pass and access arguments to a script in linux?
How to replace following lines, catch (DAOException e) { objLogger.error(this.getClass () + "addUpdateIssues() " + e); throw new BOException(5122); } catch (BOException e) { objLogger.error(this.getClass () + "addUpdateIssues() " + e); throw e; } catch (Exception e) { objLogger.error(this.getClass () + "addUpdateIssues() " + e); throw new BOException(5122); } Needs to be changed in to, catch (DAOException e) { AppException.handleException (null, null, e, null, null, null, "BOException", this.getClass() + "addUpdateIssues() ", null, null, null, null, null, null, null, null, 5122); } catch (BOException e) { AppException.handleException (null, null, null, e, null, null, "BOException", this.getClass() + "addUpdateIssues() ", null, null, null, null, null, null, null, null, 0); } catch (Exception e) { AppException.handleException (null, null, null, null, null, e, "BOException", this.getClass() + "addUpdateIssues() ", null, null, null, null, null, null, null, null, 5122); }
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