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char ch=10;printf("%d",ch);what is the output
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Answer / abdur rab
The output will be 10.
char consists of 1 byte = 8 bits
it can hold any value between 0 - 127
an unsigned char can hold any 0 - 256
the asci value 10 is newline,
so if u format it as char using %c
printf ( "\n|%c|", ch ); the 10 is converted to new line
otherwise if u format it to int using %d, it ud print 10
| Is This Answer Correct ? | 18 Yes | 1 No |
Answer / vaibhav
it prints the ascii value of 10. inthese case ineger 10
will occupy only 1 byte.
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / rogerthatrambo
although i know the answer:
what should be output of this:
do it without running.
int main()
{
char ch='48';
printf("%d %c",ch,ch);
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / yash
my output is for
What is output of followingvoid main() [3]
{char ch;for(ch=0;ch<=127;ch)printf("%c %d \n", ch, ch);}
ans: 1024
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / rahul shrivastava
surely ans will be 10.
bcz we are using %d access specifire..if we will use %c then
correnponding symbol of asciii valut 10 will be display(but
is becoms invisible)
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / devvv
this program is gonna give output 10.coz ascii values are
assigned to only 0....9.when we execute printf("%
c",ch);.........the output screen will be blank.
| Is This Answer Correct ? | 1 Yes | 4 No |
Answer / marc
58
Ascii of '0' is 48
thus, ascii of '10' is 48+10=58
| Is This Answer Correct ? | 6 Yes | 14 No |
what wud be the output? main() { char *str[]={ "MANISH" "KUMAR" "CHOUDHARY" }; printf("\nstring1=%s",str[0]); printf("\nstring2=%s",str[1]); printf("\nstring3=%s",str[2]); a)string1=Manish string2=Kumar string3=Choudhary b)string1=Manish string2=Manish string3=Manish c)string1=Manish Kumar Choudhary string2=(null) string3=(null) d)Compiler error
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