Given an array of size n+1 which contains all the numbers from 1 to n.Find the number which is repeated in O(n) time.How do you proceed with the same with floating numbers from 0 to 1 instead of 1 to n?
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What is SAP TAO? · Which Version you are using? · What is the Latest Version in SAP TAO? · What are the Advantages in SAP TAO? · What are the Patches required for SAP TAO? · What is BPT? · Difference between BPT & SAP TAO? · Which Framework using for SAP TAO? · What is CBASE? · What is the SAP TAO Architecture? · What are the Prerequisites for SAP TAO? · SAP Solution Manager Mandatory for SAP TAO 1.0? · SAP Solution Manager Mandatory for SAP TAO 2.X? · What is UI Scanner? · What is Inspector? · How many ways to Create a components using TAO 1.0? · How many ways to Create a components using TAO 2.x? · Which service pack required for SAP TAO 2.7? · What is Import/Export? · What is Consolidate?
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Given an array of size n. It contains numbers in the range 1 to n. Each number is present at least once except for 1 number. Find the missing number