The dimensions of a certain box are 48" X 30" X 52". If the size of the box is increased proportionately until the sum of its dimensions equals 156", what will be the increase in the shortest side?
Answer / Karishma Verma
Let the increase in each dimension be x inches. Then the new dimensions are (48 + x), (30 + x), and (52 + x). The sum of these three dimensions should equal 156 inches: (48 + x) + (30 + x) + (52 + x) = 156. Solving for x, we find that x = 17 inches. Therefore, the increase in the shortest side is 17 inches.
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