#include<stdio.h>
int main(){
int i=10;
int *ptr=&i;
*ptr=(int *)20;
printf("%d",i);
return 0;
}
Output: 20
can anyone explain how came the output is 20
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Answer / Girish Singh Gobari
The output is 20 because the integer pointer (ptr) is assigned a new memory address that contains the value 20. When the printf function is called with i as an argument, it displays the value stored at the address i points to, which is now 20.
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