Answer / sreejesh1987

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,a[3][3],rowsum[3],colsum[3];
clrscr();

for(i=0;i<3;i++)
rowsum[i]=colsum[i]=0;

printf("Enter numbers:\n");
for(i=0;i<3;i++)
for(j=0;j<3;j++)
{
scanf("%d",&a[i][j]);
rowsum[i]+=a[i][j];
colsum[j]+=a[i][j];
}


for(i=0;i<3;i++)
printf("RowSum[%d]:%d\n",i,rowsum[i]);

for(i=0;i<3;i++)
printf("Columnsum[%d]:%d\n",i,colsum[i]);

getch();
}

Answer / rowel baldemoro

#include<stdio.h>
#include <conio.h>
#include <windows.h>
#include <iostream>

using namespace std;
void design(int x, int y){

COORD coord;
coord.X=x;
coord.Y=y;
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE),coord);


}
int main()
{

int no[3][3],sum[2][3];

//1x3
design(1,0);
cin>>no[0][0];

design(4,0);
cin>>no[0][1];

design(7,0);
cin>>no[0][2];
sum[0][0]=no[0][0]+no[0][1]+no[0][2];

design(8,0);
printf("=%d",sum[0][0]);
//2x3
design(1,2);
cin>>no[1][0];

design(4,2);
cin>>no[1][1];

design(7,2);
cin>>no[1][2];
sum[0][1]=no[1][0]+no[1][1]+no[1][2];

design(8,2);
printf("=%d",sum[0][1]);
//3x3
design(1,4);
cin>>no[2][0];

design(4,4);
cin>>no[2][1];

design(7,4);
cin>>no[2][2];
sum[0][2]=no[2][0]+no[2][1]+no[2][2];

design(8,4);
printf("=%d",sum[0][2]);

sum[1][0]=0;
for(int i=0;i<3;i++){
design(1,6);

sum[1][0]=sum[1][0]+no[i][0];
cout<<sum[1][0];
}
design(4,6);


design(7,6);

getch();
}

What is the time complexity T(n) of the following program? a) int n, d, i, j; cin >> n; for (d=1; d<=n; d++) for (i=1; i<=d; i++) for (j=1; j<=n; j += n/10) cout << d << " " << i << " " << j << endl; b) void main() { int n, s, t; cin >> n; for (s = 1; s <= n/4; s++) {t = s; while (t >= 1) { cout << s << " " << t << endl; t--; } } } c) void main() { int n, r, s, t; cin >> n; for (r = 2; r <= n; r = r * 2) for (s = 1; s <= n/4; s++) { t = s; while (t >= 1) { cout << s << " " << t << endl; t--; } } }

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