hai friends i already ask this question but when i post the question the alignm

hai friends i already ask this question but when i post the
question the alignment goes wrong .....my question is we
have a WEB TABLE ....assume that web table having 3 row's
and 3 column here in 2nd row 3rd column having VISIT
FACEBOOK link...now i want to check the VISIT FACEBOOK link
is available or not ..if it's there i want to click the link
...then how to find the web table row or column count
....don't write the excel or data table script here friends
.....consider that it's a WEB TABLE do a favour ...thank's

Question Posted / rajesh

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hai friends i already ask this question but when i post the question the alignment goes wrong .......

Answer / mogal

Set OWT = Browser(" ").Page(" " ).WebTable( " ")
CC = OWT.ColumnCount
GetRNum = OWT.GetRowWithCellText("VISIT FACEBOOK")
For j =1 to CC step 1
If OWT.GetCelldata(GetRNum,j) = "VISIT FACEBOOK" Then
GetCNum = j
Exit for
End If
Next
Set Link1 = OWT.ChildItem(GetRNum,GetCNum,"Link",0)
Link1.Click

(or)
Set OWT = Browser(" ").Page(" " ).WebTable( " ")
RC = OWT.RowCount
CC = OWT.ColumnCount (1)
For i =1 to RC
For j= i to CC
If OWT.GetCellData(i,j) = "VISIT FACEBOOK" Then
GetRNum = i
GetCNum = j
Exit for
Exit for
End If
Next
Next
Set Link1 = OWT.ChildItem(GetRNum,GetCNum,"Link",0)
Link1.Click

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hai friends i already ask this question but when i post the question the alignment goes wrong .......

Answer / ram

Hi,
You can use GetTableFromElement by putting in loop.

Let me know if you want code.

Ram

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0 No

hai friends i already ask this question but when i post the question the alignment goes wrong .......

Answer / pravati

Rowcount=B().P().webtable().getrowcount
for i=0 to Rowcount-1
msgbox i,..it willshow u no of rows
next
clmncnt=B().P().webtable().getcolumncount
for j=0 to clmncnt-1
msgbox j,....it will show u no of columns
next
B().P().webtable().Getcelldata(2,3).click
wait 2
if B().p().link().exists then
msgbox " link exists
else
msgbox "link doesnot exists"

Is This Answer Correct ?

0 Yes

0 No

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