hai friends i already ask this question but when i post the
question the alignment goes wrong .....my question is we
have a WEB TABLE ....assume that web table having 3 row's
and 3 column here in 2nd row 3rd column having VISIT
FACEBOOK link...now i want to check the VISIT FACEBOOK link
is available or not ..if it's there i want to click the link
...then how to find the web table row or column count
....don't write the excel or data table script here friends
.....consider that it's a WEB TABLE do a favour ...thank's
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Set OWT = Browser(" ").Page(" " ).WebTable( " ")
CC = OWT.ColumnCount
GetRNum = OWT.GetRowWithCellText("VISIT FACEBOOK")
For j =1 to CC step 1
If OWT.GetCelldata(GetRNum,j) = "VISIT FACEBOOK" Then
GetCNum = j
Exit for
End If
Next
Set Link1 = OWT.ChildItem(GetRNum,GetCNum,"Link",0)
Link1.Click
(or)
Set OWT = Browser(" ").Page(" " ).WebTable( " ")
RC = OWT.RowCount
CC = OWT.ColumnCount (1)
For i =1 to RC
For j= i to CC
If OWT.GetCellData(i,j) = "VISIT FACEBOOK" Then
GetRNum = i
GetCNum = j
Exit for
Exit for
End If
Next
Next
Set Link1 = OWT.ChildItem(GetRNum,GetCNum,"Link",0)
Link1.Click
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / ram
Hi,
You can use GetTableFromElement by putting in loop.
Let me know if you want code.
Ram
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / pravati
Rowcount=B().P().webtable().getrowcount
for i=0 to Rowcount-1
msgbox i,..it willshow u no of rows
next
clmncnt=B().P().webtable().getcolumncount
for j=0 to clmncnt-1
msgbox j,....it will show u no of columns
next
B().P().webtable().Getcelldata(2,3).click
wait 2
if B().p().link().exists then
msgbox " link exists
else
msgbox "link doesnot exists"
| Is This Answer Correct ? | 0 Yes | 0 No |
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