Answer / sj

for inscribed hexagon:area of hexagon=6*area of one trangle =6*√3/4(10)^2=150√3
for circumscribed hexagon:
tan 30=l/r=>l=10/√3
one side of hexagon=20/√3
area of hexagon=6*1/2*20/√3*10=600/√3
ratio =3:4

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