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how to add two numbers without using arithmetic operators?
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Answer / sanjay bhosale
int x=12382,y=2;
int xor, and, temp;
and = x & y;
xor = x ^ y;
while(and != 0 )
{
and <<= 1;
temp = xor ^ and;
and &= xor;
xor = temp;
}
printf(" sum is : %d",xor);
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / shashishekar
#include<stdio.h>
#include<conio.h>
int main()
{
int a= 10;
int b=5;
int sum=0;
sum= a-(~b)-1;
printf(" sum= %d",sum);
getch();
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / mallikarjun
#include<stdio.h>
#include<conio.h>
main()
{
int a= 10;
int b=5;
sum=0;
sum= a&&b;
printf(" sum= %d",sum);
}
| Is This Answer Correct ? | 9 Yes | 10 No |
Answer / rajkumar
#include<stdio.h>
#include<conio.h>
void main()
{
int a=6,b=3,sum=0;
sum=a^b;
printf("sum=%d",sum);
getch();
}
| Is This Answer Correct ? | 3 Yes | 9 No |
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#include <stdio.h> int main ( int argc, char* argv [ ] ) { int value1 = 10; int value2 = 5; printf ( "\n The sum is :%d", value1 | value2 ); } This is the answer asked by some one to add two numbers with out using arithmetic operator?Yes this answer is write it given out put as 15.But how????? what is need of following line? int main ( int argc, char* argv [ ] ) how it work?what is the meaning for this line? please explain me.Advance thanks
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C 
