Answer / ram

If four letters are different, then with each letter there
are two possibilities, i.e. A letter can be posted in either
of two mailboxes.

Total no. of ways = 2^4 = 16.

Answer / wwwwwwwwwwwwwww

matherchod log nahi pata hao to galat ans kahe ko post krta be

Answer / binesh

I think the robbins way
is right. But i couldnt
under stand why did
he multiply the result
by 2

the chances are
none in the fist box
and all in the other
box=4C0=1
1 in fist and 3 in
second=4C1=4
2 in first and 2 in
second=4C2=6
3 in first and 1 in
second=4C3=4
4 in fist and none in
second=4C4=1

so net chance is
4C0+4C1+4C2+4C3+4C4=16

Answer / koustav chakraborty

as for question have to post atleast 1 letter in 2 box.. i think the posibilty to post 4 letter in 2 box is 3 ..cause
1st box 1 letter and 2nd box 3 letter,
1st box 2 letter and 2nd box 2 letter,
1st box 3 letter and 2nd box 1 letter.

Answer / arun jain

4! * 3!=144

Answer / lester

If the letters are thought to be unique than the answer is: 2*2*2*2=8
If the letters are thought to be identical(as in spam mails) than the answer is:
(5,0,0) (4,1,0) (3,2,0) (2,3,0) (1,4,0) (0,5,0)
(4,0,1) (3,1,1) (2,2,1) (1,3,1) (0,4,1)
(3,0,2) (2,1,2) (1,2,2) (0,3,2)
(2,0,3) (1,1,3) (0,2,3)
(1,0,4) (0,1,4)
(0,0,5)
1+2+3+4+5+6 = 21 ways
~Lester

Answer / tony

12 ways

Answer / shanthini.pr93@gmail.com

2

Answer / karthika

Assume 1st box 4 letter and 2nd box no letter,
1st box 1 letter and 2nd box 3 letter,
1st box 2 letter and 2nd box 2 letter,
1st box 3 letter and 2nd box 1 letter,
1st box not post and 2nd box 4 letter,
1st box 3 letter and 2nd box 1 letter,

so totally 6ways

Answer / priya

1 way=1-3
2 way=2-2
3 way=3-1
4 way=4-0
5 way=0-4
answer 5

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