Answer / ashok kumar

str = "HELLO WORLD"
Set regex = New RegExp
regex.pattern = "L"
regex.Global = True
Set matches = regex.Execute(str)
msgbox matches.count

Answer / nagk24

here one more using loops and inbuilt functions

cnt=0
a="HELLO WORLD"
For i=1 to len(a)
n=mid(a,i,1)
If asc(n)=asc("L")Then
cnt=cnt+1
End If
Next
print cnt

Answer / rajasekar

dim str,strcount,strdis
str="welcome"
strcount=split(str,"l")
strdis=ubound(strcount)
print "count" & strdis

Answer / haneef

Hi..Ashok Kumar thank you yaar....its working.

->Hani<-

Answer / srikanthdas

str = "HELLO WORLD"
str1=Replace(str,"L","")
cnt=len(str)-len(str1)

msgbox "Number of L's in str is:" cnt

Hi,Sudhanandareddy plz forword framework and ppts for QTP to me. This is my mail id: ranjith_99reddy@yahoo.co.in (your contact number also)

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