I need your help, i need a Turbo C code for this problem..
hope u'll help me guys.?
Your program will have a 3x3 array. The user will input the
sum of each row and each column. Then the user will input 3
values and store them anywhere, or any location or index,
temporarily in the array. Your program will supply the
remaining six (6) values and determine the exact location of
each value in the array.
Example:
Input: Sum of row 1: 6
Sum of row 2: 15
Sum of row 3: 24
Sum of column 1: 12
Sum of column 2: 15
Sum of column 3: 18
Value 1: 3
Value 2: 5
Value 3: 6
Output: Sum of Row
1 2 3 6
4 5 6 15
7 8 9 24
Sum of Column
12 15 18
Note: Your program will not necessary sort the walues in the
array
Thanks..
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hello sir,is there any function in C that can calculate number of digits in an int type variable,suppose:int a=123; 3 digits in a.what ll b answer?
struct point { int x; int y; }; struct point origin,*pp; main() { pp=&origin; printf("origin is(%d%d)\n",(*pp).x,(*pp).y); printf("origin is (%d%d)\n",pp->x,pp->y); }
Write a C program that defines a 2-dimentional integer array called A [50][50]. Then the elements of this array should randomly be initialized either to 1 or 0. The program should then print out all the elements in the diagonal (i.e. a[0][0], a[1][1],a[2][2], a[3][3], ……..a[49][49]). Finally, print out how many zeros and ones in the diagonal.
struct Foo { char *pName; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); strcpy(obj->pName,"Your Name"); printf("%s", obj->pName); } a. Your Name b. compile error c. Name d. Runtime error
main() { signed int bit=512, mBit; { mBit = ~bit; bit = bit & ~bit ; printf("%d %d", bit, mBit); } } a. 0, 0 b. 0, 513 c. 512, 0 d. 0, -513
3 Answers HCL, Logical Computers,
pls anyone can help me to write a code to print the values in words for any value.Example:1034 to print as "one thousand and thirty four only"
prog. to produce 1 2 3 4 5 6 7 8 9 10
#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s=malloc(sizeof(struct xx)); printf("%d",s->x); printf("%s",s->name); }
main( ) { int a[ ] = {10,20,30,40,50},j,*p; for(j=0; j<5; j++) { printf(“%d” ,*a); a++; } p = a; for(j=0; j<5; j++) { printf(“%d ” ,*p); p++; } }
Write a C program to print ‘Campus Force training’ without using even a single semicolon in the program.
main() { char a[4]="HELL"; printf("%s",a); }
int i,j; for(i=0;i<=10;i++) { j+=5; assert(i<5); }