Answer / letskools

#include<stdio.h>
#include<conio.h>
void main()
{
int a[5];
int i, j,rem,k=0,x=1;
int num;
printf("enter any number");
scanf("%d",&num);
while(num>0)
{
rem = num % 10;
a[k] = rem * x;
x *= 10;
k++;
num /= 10;
}
for (i = k-1; i >= 0; i--)
{
printf("%d\n"a[i]);
}
getch();
}

Answer / charusheela

#include<stdio.h>
#include<conio.h>
void main(){
int num=123,r,i=1;
clrscr();
while(num)
{
r=num%10;
printf("%d\n",r*i);
i*=10;
num/=10;
}
getch();
}

Answer / dhruv sharma rkdf

#include<stdio.h>
#include<conio.h>
void main(){
int n,temp,i=1;
clrscr();
printf("enter number:");
scanf("%d",&n);
for(;n>0;n=n/10){
temp=(n%10)*i;
i*=10;
printf("%d\n",temp)
}
getch();
}

Answer / cute_boy4434

PLz reply me soon . ya

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