#include<conio.h> #include<stdio.h> void main() { int i; if(1,0

#include<conio.h>
#include<stdio.h>
void main()
{
int i;
if(1,0,2,3)
{
printf("if");
}
else
{
printf("else");
}
getch();
}
Can any body tell the answer of this question with explanation?

Question Posted / dheerendra

3 Answers
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#include<conio.h> #include<stdio.h> void main() { int i; if(1,0,2,3) { printf(&qu..

Answer / shyamkumar1221

the question might be like this
#include<conio.h>
#include<stdio.h>
void main()
{
int i=1;
intj=0,k=2,l=3;
if(i,j,k,l)
{
printf("if");
}
else
{
printf("else");
}
getch();
}
the output would be if
since in the if ()we are using comma operator.the precedence
is left to right...since in the if the we get output as 3
which is non zero.the if statement is true and if statement
will be printed

Is This Answer Correct ?

11 Yes

1 No

#include<conio.h> #include<stdio.h> void main() { int i; if(1,0,2,3) { printf(&qu..

Answer / guest

yhaa... it will print if....... okay...

why u know.... because in if condition u r not checking any
conditions... thatis why,,,,,

Is This Answer Correct ?

0 Yes

1 No

#include<conio.h> #include<stdio.h> void main() { int i; if(1,0,2,3) { printf(&qu..

Answer / prateek songara

By default "i" will posses the value 2 bcoz of "int" and when it moves to "if" it will check all the values matches with its value (1,0,2,3) and if he gets the match then it will print the "if" ..else it will print the "else"..........hope you got the answer now.

Is This Answer Correct ?

1 Yes

4 No

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