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How can I set an array's size at run time?
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Answer / suman
by using calloc() or malloc() functions we create at run
time
i think it will be correct if not forgive me
sumankumar..........
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / shalabh
This can be done by using malloc...if u have an integer
array then ...you can ask user the size..and then allocate
memory for integers...at the run time...using malloc()
| Is This Answer Correct ? | 4 Yes | 0 No |
You can't do that in C. Use dynamic allocation method
to implement array. See Q. 20 and 41 in
http://www.geocities.com/vijoeyz/faq/
Best,
Vijay Zanvar,
Home Page - http://geocities.com/vijoeyz/
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / lp
Declare a integer array size at runtime:
1.declare an interget pointer. - int *ptr
2.Get the size of array from user - int n
3.using malloc() ,allocate that many number of location to
the pointer. - ptr = malloc(n*sizeof(int));
4.Make use of the dynamically allocated array. - ptr[]
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / rajendra
#include <stdlib.h> /* EXIT_FAILURE, EXIT_SUCCESS */
#include <errno.h>
#include <stdio.h>
#define ROW 5
#define COL 5
int
main ( void )
{
int **cont_arr;
int **cont_arr;
int **arr = malloc ( ROW * sizeof ( int * ) );
if ( !arr )
{
perror ( "Error" );
exit ( EXIT_FAILURE );
}
for ( i=0; i < ROW; i++ )
{
arr[i] = malloc ( sizeof ( int ) * COL );
if ( !arr[i] )
{
perror ( "Error" );
exit ( EXIT_FAILURE );
}
}
/*
* Contiguous memory allocated for array.
Below.
*/
cont_arr = (int **) malloc ( ROW * sizeof ( int
* ) );
if ( !cont_arr )
{
perror ( "Error" );
exit ( EXIT_FAILURE );
}
cont_arr[0] = (int *) malloc ( ROW * COL *
sizeof ( int ) );
if ( !cont_arr[0] )
{
perror ( "Error" );
exit ( EXIT_FAILURE );
}
for ( int i=1; i < ROW; i++ )
cont_arr[i] = cont_arr[0] + i * COL;
exit ( EXIT_SUCCESS );
}
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / vinod
C99 and above supports the conceptof VLA(Variable Length Array) which allows you to set array size based on input during run time. It can also done using dynamic memory allocation.
Example:
int main()
{
int i;
scanf("%d",&i);
int a[i];
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / nithin
int main()
{
int i, max;
// Array
int *a;
printf("Enter the size of array\n");
scanf("%d", &max);
//Run time size allocation of an array
a = (int*)malloc(max * sizeof(int));
for(i = 0; i < max;i++)
{
a[i] = i * 2;
printf("value of element %d is %d\n", i, a
[i]);
}
return 0;
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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