Answer / suman

by using calloc() or malloc() functions we create at run
time


i think it will be correct if not forgive me

sumankumar..........

Answer / shalabh

This can be done by using malloc...if u have an integer
array then ...you can ask user the size..and then allocate
memory for integers...at the run time...using malloc()

Answer / vijay zanvar

You can't do that in C. Use dynamic allocation method
to implement array. See Q. 20 and 41 in
http://www.geocities.com/vijoeyz/faq/

Best,
Vijay Zanvar,
Home Page - http://geocities.com/vijoeyz/

Answer / lp

Declare a integer array size at runtime:
1.declare an interget pointer. - int *ptr
2.Get the size of array from user - int n
3.using malloc() ,allocate that many number of location to
the pointer. - ptr = malloc(n*sizeof(int));
4.Make use of the dynamically allocated array. - ptr[]

Answer / rajendra

#include <stdlib.h> /* EXIT_FAILURE, EXIT_SUCCESS */
#include <errno.h>
#include <stdio.h>

#define ROW 5
#define COL 5

int
main ( void )
{
int **cont_arr;
int **cont_arr;

int **arr = malloc ( ROW * sizeof ( int * ) );
if ( !arr )
{
perror ( "Error" );
exit ( EXIT_FAILURE );
}

for ( i=0; i < ROW; i++ )
{
arr[i] = malloc ( sizeof ( int ) * COL );
if ( !arr[i] )
{
perror ( "Error" );
exit ( EXIT_FAILURE );
}
}

/*
* Contiguous memory allocated for array.
Below.
*/

cont_arr = (int **) malloc ( ROW * sizeof ( int
* ) );
if ( !cont_arr )
{
perror ( "Error" );
exit ( EXIT_FAILURE );
}

cont_arr[0] = (int *) malloc ( ROW * COL *
sizeof ( int ) );
if ( !cont_arr[0] )
{
perror ( "Error" );
exit ( EXIT_FAILURE );
}

for ( int i=1; i < ROW; i++ )
cont_arr[i] = cont_arr[0] + i * COL;

exit ( EXIT_SUCCESS );
}

Answer / vinod

C99 and above supports the conceptof VLA(Variable Length Array) which allows you to set array size based on input during run time. It can also done using dynamic memory allocation.

Example:
int main()
{
int i;
scanf("%d",&i);
int a[i];
}

Answer / nithin

int main()
{
int i, max;

// Array
int *a;

printf("Enter the size of array\n");
scanf("%d", &max);

//Run time size allocation of an array
a = (int*)malloc(max * sizeof(int));

for(i = 0; i < max;i++)
{
a[i] = i * 2;
printf("value of element %d is %d\n", i, a
[i]);
}
return 0;
}

Answer / shruti

that is the main drawback of an array..
u cannot assign memory at run time...

Answer / arthy

main()
{
int n,i;
scanf("%d",&n);
int a[n];
}

#include<std.h> int main() { char *str[]={"Frogs","Do","Not","Die","They","Croak!"}; printf("%d %d\n",sizeof(str),strlen(str)); ...return 0; } what will the output of the above program?

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Is c is a low level language?

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Write a program to produce the following output: 1 2 3 4 5 6 7 8 9 10

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What is the difference between malloc() and calloc()?

3 Answers  

size maximum allocated by calloc()

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