Answer / d乇乇pansh

AS ,There are some readers such that in each
occupied reading spot there are different numbers of
readers.
1+2+3+4+5+6+7+8= 36 readers

so ,8 spots have different readers.
remainings are 23-8= 15.

15 spots are empty.

Answer / mayank katiyar

by default we have to consider max tables should remain empty.
so 1+2+3+4+5+6+7+8=36readers
therefore
23-8seats=15.

Answer / hari

he just said that in each different spot there are different
number of readers. So there will be many possibilities...

It is same as number of ways in which you can make a sum of
9 using only digits from 1 to 9 each at most once...

Consider
1+2+3+6+7+8+9 = 36

In this case answer is: 23-7 = 16

but different answers are possible depending on case u choose

Answer / sahanaj rahaman

max seat=9
so for different number...can write
(9+8+7+6+5+1)=36
so free spot=23-6=17

Answer / aditya agrawal

9+8+7+6+5+1= 36 readers

so ,6 spots have different readers.
remainings are 23-6= 17.

17 spots are empty.

Answer / rohit

answer 23 because everyone to ground

Answer / arun

16 is correct i take this problem 1+2+4+5+7+8+9
in this case answer is:23-7=16

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