Answer / muzammil

#include <stdio.h>
#include <conio.h>

main()
{
int a,b;
printf("Enter the values: ");
scanf("%d%d",&a,&b);
printf("The values before swapping: %d %d",a,b);
a=a-(b=(-b+(a=a+b)));
printf("The values after swapping are: %d %d",a,b);
getch();
}

Answer / r.aruna

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c;
clrscr();
printf("Enter the a value");
scanf("%d",&a);
printf("Enter the b value");
scanf("%d",&b);
a=a+b;
b=a-b;
a=a-b;
printf("After swapping a,b value",a,b);
getch();
}

Answer / muzammil

Here are some LOGICS to swap two nmbrs

1) a+=b; b=a-b; a-=b;
2) a*=b; b=a/b; a/=b;
3) a=a^b; b=a^b; a=a^b;

Now Single line statements

4) a=a-(b=(-b+(a=a+b)));
5) a=a^(b=(b^(a=a^b)));
6) b=a+b-(a=b); This one was posted BY Senthil Thanks to him
7) b=a*b/(a=b); Dis is same as above one except for da
operators.

Answer / priyamurugan

#include<stdio.h>
#include<conio.h>
main()
{
int a,b;
printf("\n BEFORE SWAPPING THE NOS");
printf("\n enter the a, b values");
scanf("%d %d",&a,&b);
swap(&a,&b);
printf("\n AFTER SWAPPING THE NOS");
printf("\n a=%d",a);
printf("\n b=%d",b);
getch();
}
swap(int *x,int *y)
{
int t;
t=*x;
*x=*y;
*y=t;
return();
}

Answer / srinivas

#include <stdio.h>

int main(void)
{
int a = 2, b = 5;

a = a + b;
b = a - b;
a = a - b;
printf("%d\t%d\n", a, b);
return 0;
}

Answer / senthil mca sns

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
clrscr();
printf("Enter the a value:");
scanf("%d",&a);
printf("Enter the b value:");
scanf("%d",&b);
b=a+b-(a=b);
printf("After Swapping a=%d,b=%d",a,b);
getch();
}

Answer / anju

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,temp;
scanf("%d%d",&a,&b);
printf("before swapping value of a=%d and b=%d",a,b);
temp=x;
x=y;
y=temp;
printf("after swapping value of a=%d and b=%d",a,b);
getch();
}

void swap(int a,int b) { a=a+b; b=a-b; a=a-b; } in this code always gives the same result for all case

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