#include<stdio.h> void main() { int a [5]; for (i=0; i<=4

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#include<stdio.h>
void main()
{
int a [5];
for (i=0; i<=4; i++)
printf(“%d” ,a[i]);
}

Question Posted / guest

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#include<stdio.h> void main() { int a [5]; for (i=0; i<=4; i++) printf(�..

Answer / kalyan chukka

Here it shows i is undefined Symbol.So if declare i as
integer then it prints some garbage value Because Array is
declared but elements are not inserted into the array.So
garbage value is printed on the console

Is This Answer Correct ?

10 Yes

1 No

#include<stdio.h> void main() { int a [5]; for (i=0; i<=4; i++) printf(�..

Answer / neelima

it gives a garbage values

Is This Answer Correct ?

10 Yes

2 No

#include<stdio.h> void main() { int a [5]; for (i=0; i<=4; i++) printf(�..

Answer / sameer mohammed

It shows us garbage values as because the integer type
array is declared but it is not defined.

Is This Answer Correct ?

6 Yes

2 No

#include<stdio.h> void main() { int a [5]; for (i=0; i<=4; i++) printf(�..

Answer / jayakrishna

here array a is declared but it is not initialised,but int
the printf we are printing values of array a[], so it
displays garbage values & cannot directly write i as
variable we must specify its type.

Is This Answer Correct ?

4 Yes

1 No

#include<stdio.h> void main() { int a [5]; for (i=0; i<=4; i++) printf(�..

Answer / tanvi jain

as i is not yet declared,so give an error.

Is This Answer Correct ?

0 Yes

0 No

#include<stdio.h> void main() { int a [5]; for (i=0; i<=4; i++) printf(�..

Answer / purnima

it gives compile time error because here the var i is not
declared .aIn c a var must be declared before is usage

Is This Answer Correct ?

0 Yes

1 No

#include<stdio.h> void main() { int a [5]; for (i=0; i<=4; i++) printf(�..

Answer / guest

0
1
2
3
4

Is This Answer Correct ?

0 Yes

5 No

#include<stdio.h> void main() { int a [5]; for (i=0; i<=4; i++) printf(�..

Answer / kapil

1 2 3 4 5

Is This Answer Correct ?

3 Yes

14 No

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