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#include<stdio.h>
void main()
{
int a [5];
for (i=0; i<=4; i++)
printf(“%d” ,a[i]);
}
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Answer Posted / jayakrishna
here array a is declared but it is not initialised,but int
the printf we are printing values of array a[], so it
displays garbage values & cannot directly write i as
variable we must specify its type.
| Is This Answer Correct ? | 4 Yes | 1 No |
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