write a program to display the numbers in the following
format
4 4
3 3 3 3
2 2 2 2 2 2
1 1 1 1 1 1 1 1
0 0 0 0 0 0 0 0 0
1 1 1 1 1 1 1
2 2 2 2 2
3 3 3
4
Answers were Sorted based on User's Feedback
Answer / vidyullatha
#include<stdio.h>
main()
{
int i=0,k=0,l=0;
int cnt=1;
int space=7;
for (i=4;i>0;i--)
{
for(l=1;l<=cnt;l++)
{
printf("%d ",i);
}
for(k=0;k<space;k++)
{
printf(" ");
}
for(l=1;l<=cnt;l++)
{
printf("%d ",i);
}
cnt++;
space=space-2;
printf("\n");
}
for(i=0;i<9;i++)
{
printf("0 ");
}
printf("\n");
cnt=7;
for(i=1;i<=4;i++)
{
for(k=0;k<i;k++)
printf(" ");
for(l=1;l<=cnt;l++)
{
printf("%d ",i);
}
printf("\n");
cnt=cnt-2;
}
}
Is This Answer Correct ? | 19 Yes | 1 No |
Answer / jankipatel
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,k,l,p;
clrscr();
// printf("enter the value\n");
// scanf("%d",&l);
for(i=4;i>=0;i--)
{
for(j=4;j>=i;j--)
{
// textcolor(0-i);
printf("%d ",i);
}
for(k=0;k<=i-1;k++)
{
printf(" ");
}
for(k=0;k<=i-1;k++)
{
printf(" ");
}
for(j=4;j>=i;j--)
{
// textcolor(0-i);
printf(" %d",i);
}
printf("\n");
}
for(i=1;i<=4;i++)
{
for(j=1;j<=i;j++)
{
printf(" ");
}
for(k=4;k>=i;k--)
{
printf("%d ",i);
}
for(k=4;k>=i;k--)
{
printf(" %d",i);
}
printf("\n");
}
getch();
}
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / meet parikh
public class Arrow_1 {
private final int LARG = 4;
String printint,fillint;
boolean display = false;
public Arrow_1(){
fillint = " ";
for(int i = LARG; i >= 0; i--){
if(i == 0){
display = true;
fillint = 0 + "";
}
StringBuilder sb = new StringBuilder();
printint = i + "";
insertDisp(sb, i);
System.out.println(sb.toString());
}
printint = " ";
for(int i = LARG; i>0;i--){
StringBuilder sb = new StringBuilder();
fillint = LARG - (i-1) + "";
insertDisp(sb,i);
System.out.println(sb.toString());
}
}
private void insertDisp(StringBuilder sb,int number){
printDisp(sb, number);
fillempty(sb, number);
if(display){
sb.append(fillint);
} else {
sb.append(" ");
}
fillempty(sb, number);
printDisp(sb, number);
}
private void printDisp(StringBuilder sb,int number){
int itr;
if(number == 0){
itr = LARG;
} else {
itr = LARG - (number-1);
}
for(int i = 0 ; i < itr;i++){
sb.append(printint);
}
}
private void fillempty(StringBuilder sb, int number){
for(int i = 0; i < number-1 ;i++ ){
sb.append(fillint);
}
}
public static void main(String args[]){
new Arrow_1();
}
}
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / padmapriya
class Pattern{
public static void main(String[]args){
for(int i=4;i>0;i--){
for(int j=0;j<5-i;j++){
System.out.print(i);
}
for(int j=0;j<i;j++){
System.out.print(" ");
}
for(int j=0;j<i-1;j++){
System.out.print(" ");
}
for(int j=0;j<5-i;j++){
System.out.print(i);
}
System.out.println();
}
for(int i=0;i<5;i++){
for(int j=0;j<i;j++){
System.out.print(" ");
}
for(int j=0;j<9-2*i;j++){
System.out.print(i);
}
System.out.println();
}
}
}
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / mahesh
#include<stdio.h>
int main()
{
int a=2,n=4,i,j,k;
for (i=4;i>=0;i--)
{
for(j=0;j<a;j++)
{
printf("%d",n);
}
printf("
");
a=a+2;
n--;
}
n=1;
a=a-4;
for(i=0;i<=4;i++)
{
for(j=0;j<a;j++)
{
printf("%d",n);
}
printf("
");
a=a-2;
n++;
}
}
Is This Answer Correct ? | 2 Yes | 1 No |
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,k,l,n;
clrscr();
printf("enter the number");
scanf("%d",&n);
for(j=n,l=1;(j>0 && l<=n);j--,l++)
{
for(k=1;k<=2*l;k++)
printf("%d",j);
printf("
");
}
for(j=0,l=n;(j<=n && l>=0) ;j++,l--)
{
for(k=1;k<=2*l+1;k++)
printf("%d",j);
printf("
");
}
getch();
}
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / vamsi talapatra
#include<iostream>
using namespace std;
int main(){
int n = 4;
int e = 2;
while(n>0){
for(int i = 0; i< e ; i++){
cout<<n<<" ";
}
cout<<endl;
e=e+2;
n--;
}
while(n<=4){
for(int i = 1; i< e ; i++){
cout<<n<<" ";
}
cout<<endl;
e=e-2;
n++;
}
return 0;
}
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / venkatesh
#include <stdio.h>
#include <stdlib.h>
/* run this program using the console pauser or add your own getch, system("pause") or input loop */
int main(int argc, char *argv[]) {
int i,j,k,n1,n2;
printf("
enter n1 value:");
scanf("%d",&n1);
k=4;
for(i=1;i<=n1;)
{
for(j=i;j<=2*i;j++)
{
printf("%d ",k);
}
printf("
");
i=i+2;
k=k-1;
}
k=0;
n2=n1+1;
for(i=9;i>=1;)
{
for(j=1;j<=i;j++)
{
printf("%d ",k);
}
printf("
");
k=k+1;
i=i-2;
}
return 0;
}
Is This Answer Correct ? | 0 Yes | 1 No |
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