Interested to Buy Any Domain ? << Click Here >> for more details...
main()
{ int i;
printf("%d",((i=1)*i-- - --i*(i=-3)*i++ + ++i));
}
ans is 24 bt how?pls tell smbody............
- 3 Answers
- 8234 Views
- I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / gorgeousgirl
Answer: 34
confirm the answer with http://codepad.org/PudiZIaS
Explanation:
by order of precedence, parenthesis hav highest priority
so
(i=1)*i-- - --i*(i=-3)*i++ + ++i
i=1 i=-3
now, i=-3
after assignment operations the expr becomes,
>(i)*i-- - --i*(i)*i++ + ++i
next higher priority is for auto-in/decrement
omitting post in/decrement(as they hav effect only after
this line of code), we get,
> i*i - --i*i*i + ++i
the associativity for printf statement is from right to left
so ++i is executed first before --i where i=-3
> i*i - --i*i*i + -2
now i=-2
> i*i - -3*i*i + -2
now i =-3
next precedence is for multiplication
> -3*-3
-
-3*-3*-3
+
-2
> 9 - -27 + -2
> 9 + 27 -2
> 9 + 25
> 34
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / sureshb
value is 26 and i value is -2.
Intiallay i=1 is assiged.
((i=1)*i--) 1st expression = 1 postfix decrement evaluates at the end.
now i=1
--i => 0. 2nd expression
i=-3 assigned new value 3rd expression.
-3*-3 => 9 *(-3) => -27
++ post increment done at the end
-(-27) = 27.
1+ 27 =>28
now i is -3.
++i => -2;
28-2= 26.
i=-2;
post increment and decrement happens. finaaly i = -2.
| Is This Answer Correct ? | 5 Yes | 3 No |
Answer / rama krishna sidhartha
Actually answer is not 24 it is -7567. When i executed this
in the turbo c compiler i got the answer like that.
| Is This Answer Correct ? | 0 Yes | 2 No |
At a shop of marbles, packs of marbles are prepared. Packets are named A, B, C, D, E …….. All packets are kept in a VERTICAL SHELF in random order. Any numbers of packets with these names could be kept in that shelf as in this example: bottom of shelf ---> [AAAJKRDFDEWAAYFYYKK]-----Top of shelf. All these packets are to be loaded on cars. The cars are lined in order, so that the packet could be loaded on them. The cars are also named [A, B, C, D, E,………….]. Each Car will load the packet with the same alphabet. So, for example, car ‘A’ will load all the packets with name ‘A’. Each particular car will come at the loading point only once. The cars will come at the loading point in alphabetical order. So, car ‘B’ will come and take all the packets with name ‘B’ from the shelf, then car ‘C’ will come. No matter how deep in the shelf any packet ‘B’ is, all of the ‘B’ packets will be displaced before the ‘C’ car arrives. For that purpose, some additional shelves are provided. The packets which are after the packet B, are kept in those shelves. Any one of these shelves contains only packets, having the same name. For example, if any particular shelf is used and if a packet with name X is in it, then only the packets having names X will be kept in it. That shelf will look like [XXXXXXX]. If any shelf is used once, then it could be used again only if it is vacant. Packets from the initial shelf could be unloaded from top only. Write a program that finds the minimum total number of shelves, including the initial one required for this loading process.
what is the structure pointer?
How to set file pointer to beginning c?
What are the 5 organizational structures?
I have a varargs function which accepts a float parameter?
What are the standard predefined macros?
If null and 0 are equivalent as null pointer constants, which should I use?
what are the static variables
8 Answers HCL, iFlex, TCS, Wipro,
What is the use of in c?
how to use enum datatype?Please explain me?
What is ## preprocessor operator in c?
a.One Cannot Take the address of a Bit Field b.bit fields cannot be arrayed c.Bit-Fields are machine Dependant d.Bit-fields cannot be declared as static Which of the Following Statements are true w.r.t Bit-Fields A)a,b&c B)Only a & b C)Only c D)All
3 Answers Accenture, Digg.com,
C 
