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main()
{ int i;
printf("%d",((i=1)*i-- - --i*(i=-3)*i++ + ++i));
}
ans is 24 bt how?pls tell smbody............
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Answer Posted / sureshb
value is 26 and i value is -2.
Intiallay i=1 is assiged.
((i=1)*i--) 1st expression = 1 postfix decrement evaluates at the end.
now i=1
--i => 0. 2nd expression
i=-3 assigned new value 3rd expression.
-3*-3 => 9 *(-3) => -27
++ post increment done at the end
-(-27) = 27.
1+ 27 =>28
now i is -3.
++i => -2;
28-2= 26.
i=-2;
post increment and decrement happens. finaaly i = -2.
| Is This Answer Correct ? | 5 Yes | 3 No |
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