Answer / satish kumar

void union(int x[],int y[])
{


int n=x.length + y.length ;
int z[]=new int[n];
int p=x.length;
for(int i=0;i<x.length;i++)
{
z[i]=x[i];
}
int j=0;
for(int i=0;i<y.length;i++)
{
for(j=0;j<x.length;j++)
{
if(y[i]!=z[j])
{
continue;
}
else
{
if(y[i]==z[j])

break;
}
}
if(j==x.length)
z[p++]=y[i];
}

Answer / nadeem khokhar

the above mentioned code is also good one. but i m giving you an algorithm you can say, so you can get the concept and convert it into any language
int a[3]=1,2,3;
int b[3]=2,3,4;

for(int i=0; i <=2; i++)
{

for(int j=0; j<=2; j++)
{

if(a[i] == b[j])
cout<<a[i]; is a union of a and b
}
}

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