Answer Posted / nadeem khokhar

the above mentioned code is also good one. but i m giving you an algorithm you can say, so you can get the concept and convert it into any language
int a[3]=1,2,3;
int b[3]=2,3,4;

for(int i=0; i <=2; i++)
{

for(int j=0; j<=2; j++)
{

if(a[i] == b[j])
cout<<a[i]; is a union of a and b
}
}

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