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struct point

{

int x;

int y;

};

struct point origin,*pp;

main()

{

pp=&origin;

printf("origin is(%d%d)\n",(*pp).x,(*pp).y);

printf("origin is (%d%d)\n",pp->x,pp->y);

}



struct point { int x; int y; }; struct point origin..

Answer / susie

Answer :

origin is(0,0)

origin is(0,0)

Explanation:

pp is a pointer to structure. we can access the elements of
the structure either with arrow mark or with indirection
operator.

Note:

Since structure point is globally declared x & y are
initialized as zeroes

Is This Answer Correct ?    4 Yes 0 No

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