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Answer / ejaz
In two classes(having parent child/common interface
relation) methods with same signature and execution of
method decided at run time based on object type.
|Is This Answer Correct ?||4 Yes||0 No|
Answer / vic
To elaborate on Ejaz's answer, the run time determination
will only happen if the functions being called were declared
as being virtual.
If they weren't, then the function to be called will be
determined at compile time according to the object type.
|Is This Answer Correct ?||0 Yes||0 No|
Answer / kamal
same function name and same argument list
|Is This Answer Correct ?||5 Yes||6 No|
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