Answer / susie

Answer :

Compiler Error

Explanation:

The expression i+++++i is parsed as i ++ ++ + i which is an
illegal combination of operators.

Answer / ashi rathore

Ans is 11, as i+++++i can be written as i++ + ++i.
i++ =5
++i = 6
then 5 + 6 = 11

Answer / lucky varshney

i=6

main() { char str1[] = {‘s’,’o’,’m’,’e’}; char str2[] = {‘s’,’o’,’m’,’e’,’\0’}; while (strcmp(str1,str2)) printf(“Strings are not equal\n”); }

1 Answers  

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union u { union u { int i; int j; }a[10]; int b[10]; }u; main() { printf("\n%d", sizeof(u)); printf(" %d", sizeof(u.a)); // printf("%d", sizeof(u.a[4].i)); } a. 4, 4, 4 b. 40, 4, 4 c. 1, 100, 1 d. 40 400 4

3 Answers   HCL,

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can u give me the c codings for converting a string into the hexa decimal form......

1 Answers  

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int a=1; printf("%d %d %d",a++,a++,a); need o/p in 'c' and what explanation too

1 Answers  

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main() { int a=10,*j; void *k; j=k=&a; j++; k++; printf("\n %u %u ",j,k); }

1 Answers  

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#include<stdio.h> int main() { int x=2,y; y=++x*x++*++x; printf("%d",y); } Output for this program is 64. can you explain how this output is come??

1 Answers  

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#define FALSE -1 #define TRUE 1 #define NULL 0 main() { if(NULL) puts("NULL"); else if(FALSE) puts("TRUE"); else puts("FALSE"); }

1 Answers  

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main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

2 Answers   CSS, Wipro,

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main() { int c = 5; printf("%d", main||c); } a. 1 b. 5 c. 0 d. none of the above

2 Answers   HCL,

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main() { int i; clrscr(); printf("%d", &i)+1; scanf("%d", i)-1; } a. Runtime error. b. Runtime error. Access violation. c. Compile error. Illegal syntax d. None of the above

1 Answers   HCL,

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source code for delete data in array for c

1 Answers   TCS,

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struct aaa{ struct aaa *prev; int i; struct aaa *next; }; main() { struct aaa abc,def,ghi,jkl; int x=100; abc.i=0;abc.prev=&jkl; abc.next=&def; def.i=1;def.prev=&abc;def.next=&ghi; ghi.i=2;ghi.prev=&def; ghi.next=&jkl; jkl.i=3;jkl.prev=&ghi;jkl.next=&abc; x=abc.next->next->prev->next->i; printf("%d",x); }

1 Answers  

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