main()
{
register int a=2;
printf("Address of a = %d",&a);
printf("Value of a = %d",a);
}
Answers were Sorted based on User's Feedback
Answer / susie
Answer :
Compier Error: '&' on register variable
Rule to Remember:
& (address of ) operator cannot be applied on register
variables.
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / chandra
It all depends on C/C++.
On C(GNU C/Visual studio C compiler), it will get a compiler
error.
since the keyword with register is stored in registers of
CPU rather than in memory locations of RAM.
On C++(GNU C++/Visual stdio C++ compiler), variable 'a' will
get an address of memory locations.
since register will automatically take address of memory
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / shrikantauti
Will produce an error as the memory address s not provided.
%u should had written instead of %d
| Is This Answer Correct ? | 0 Yes | 3 No |
String reverse with time complexity of n/2 with out using temporary variable.
void main() { int i; char a[]="\0"; if(printf("%s\n",a)) printf("Ok here \n"); else printf("Forget it\n"); }
Write a program to check whether the number is prime and also check if it there i n fibonacci series, then return true otherwise return false
void ( * abc( int, void ( *def) () ) ) ();
what is oop?
What is "far" and "near" pointers in "c"...?
main() { int i =10, j = 20; clrscr(); printf("%d, %d, ", j-- , --i); printf("%d, %d ", j++ , ++i); } a. 20, 10, 20, 10 b. 20, 9, 20, 10 c. 20, 9, 19, 10 d. 19, 9, 20, 10
main() { char a[4]="HELL"; printf("%s",a); }
what will be the output of this program? void main() { int a[]={5,10,15}; int i=0,num; num=a[++i] + ++i +(++i); printf("%d",num); }
main() { struct date; struct student { char name[30]; struct date dob; }stud; struct date { int day,month,year; }; scanf("%s%d%d%d", stud.rollno, &student.dob.day, &student.dob.month, &student.dob.year); }
void main() { int i=10, j=2; int *ip= &i, *jp = &j; int k = *ip/*jp; printf(ā%dā,k); }
main() { char *p; p="%d\n"; p++; p++; printf(p-2,300); }