Answer / jickson

#include<stdio.h>
main()
{
int num,dcount,temp,i,j;
int array[20];
printf("\nEnter a number:");
scanf("%d",&num);
temp=num;
for(dcount=0;num!=0;num=num/10,dcount++);
for(i=dcount;i>0;i--)
{
array[i-1]=temp%10;
temp=temp/10;
}
printf("Required Pattern is:\n");
for(i=0;i<dcount;i++)
{
for(j=i;j<dcount;j++)
printf("%d\t",array[j]);
printf("\n");
}

}

Answer / shams

#include <stdio.h>
int main()
{
int i,j,index,n,a[10];
printf("enter a number");
scanf("%d",&n);
for(i=0;n!=0;i++)
{
a[i]=n%10;
n=n/10;
}
i=i-1;
printf("output\n");
for(;i>=0;i--)
{
for(j=i;j>=0;j--)
printf("%d\t",a[j]);
printf("\n");
}
return 0;
}

Answer / shams

#include <iostream>
#include<stdio.h>
#include<cstdlib>
#include<unistd.h>
#include<time.h>
#include<string.h>
using namespace std;
int main()
{
int i,b,j,index,n,a[10];
printf("enter a number");
scanf("%d",&n);
b=n;
for(i=0;n!=0;i++)
{
a[i]=n%10;
n=n/10;
}
b=i;
i=i-1;
printf("output\n");
for(;i>=0;i--)
{
for(j=i;j>=0;j--)
printf("%d\t",a[j]);
printf("\n");
for(int k=0;k<b-i;k++)
printf("\t");
}
return 0;
}

Answer / akashdeep

#include<stdio.h>
void main()
{
int a,count=0,b=1,c;
printf("enter a number
");
scanf("%d",&a);
c=a;
while(a>0)
{
count=count+1;
a=a/10;
}
for(int i=0;i<(count-1);++i)
{
b=b*10;
}
while(c>0)
{
printf("%d
",c);
c=c%b;
b=b/10;
}

}

Answer / royalrdx

#include <stdio.h>
#include <math.h>

int main()
{
int n,a,count=0,b;
printf("Enter");
scanf("%d",&a);
n=a;
while(n>0){
count++;
n=n/10;
}

while (count>0)
{
b=pow(10,count);
printf("
%d
",a%b);
count--;
}
return 0;
}

Answer / md. wasifur rahman siyam

#include<stdio.h>
#include<conio.h>
int main()
{
int n,i=0,j,k=1,x,c=0,sum=0,a[100];
printf("
enter the number:");
scanf("%d",&x);
while(x!=0){
a[i++]=x%10;
x=x/10;
c++;
}
printf("
the digits are :
");
printf(" ");
for(j=c-1;j>=0;j--){
for(i=c-k;i>=0;i--){
printf("%d",a[i]);
}
printf("
");
printf(" ");
k=k+1;
}
getch();
return 0;
}

Answer / pavan_mustyala

#include <stdio.h>

int main(int argc, char* argv[])
{
int num = 15;
int i = 1;
int j = 1;

for( ; i <= num; i++)
{
for( j = i; j <= num; j++)
{
printf("%-3d ",j);
}
printf("\n\n");
}

return 0;
}

Answer / mohit

#include<stdio.h>
#include<conio.h>
main()
{
int i,j,n;
printf("enter any number : ");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(j=i;j<=n;j++)
{
printf("%d ",j);
}
printf("\n");
}
getch();
}

Given an array of size N in which every number is between 1 and N, determine if there are any duplicates in it. You are allowed to destroy the array if you like.

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