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Sir... please give some important coding questions asked by product companies..    0  27
why is printf("%d %d %d",i++,--i,i--);    2  160
In java, why do we set thread priority, when we know that there is no guarantee by which a thread should be execute?    0  257
Why we use J2ME?    1  428
What are advantages of J2ME?    1  390
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What is Generic" J2ME architecture?    0  333
Will J2SE applications run on J2ME?If Not Why?    1  382
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What is minimum hardware and Software requirements for J2ME?    1  394
Explain Virtual Machine for J2ME?    1  381
List some Property Supported by J2ME?    1  389
What hardware and software requirements of a device that intends to implement the MIDP.    1  370
Explain MIDlet Life cycle?    0  320
What are basics Software's for J2ME applications?    1  368
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i am doing my final year project about programming use verilog ,i am new about it so got problem,i want to record the readings of a waveform every 2us use the verilog code ,every ten readings i need to add them together after that i need to compare this series of number to get which one is the biggest , right now i don't know how to use code to store the readings every 2us on a waveform ,pls help me thanks a lot . 765
plzzzzzzzzz xplain this code import java.awt.*; import java.awt.event.*; import java.awt.MenuItem.*; import java.sql.*; import sun.jdbc.odbc.*; import*; public class ShopDelivery extends Frame implements ActionListener { Label l1,l2,l3,l4,l5,l6,l7,l8,l9,l10,l11,l12,l13; Button exit,save,next,top,prev,botm,ad,show; TextField txtCMemoNo,txtConsNo,txtCMemoDt,txtConsName,txtAddr1,txtPhNo ,txtBookDtold,txtPrintDt,txtOldCMemNo,txtOldDlryDt,adr2,adr3 ,tot,stnry,rmrk; String ConsName; String Addr1; public static void main(String sr[]) { new ShopDelivery().setVisible(true); } public ShopDelivery() { super("Shop Delivery"); Statement stmt; ResultSet rs; //PreparedStatement pst; Connection con; try { Class.forName ("sun.jdbc.odbc.JdbcOdbcDriver"); con=DriverManager.getConnection("jdbc:odbc:Agency"); if (con!=null); System.out.println ("connected"); stmt =con.createStatement (); } catch(Exception e1) { System.out.println (e1); } setSize(1280,800); setBackground(Color.CYAN); setLayout(null); l1=new Label("Cashmemo No"); l1.setBounds(260,60,90,30); l1.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l1.setAlignment(Label.CENTER); add(l1); l2=new Label("CONSMR NO"); l2.setBounds(30,60,90,30); l2.setFont(new Font("TimesRoman",Font.PLAIN,15)); l2.setAlignment(Label.CENTER); add(l2); l3=new Label("Book DATE"); l3.setBounds(520,60,90,30); l3.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l3.setAlignment(Label.CENTER); add(l3); l4=new Label("NAME"); l4.setBounds(30,150,45,30); l4.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l4.setAlignment(Label.CENTER); add(l4); l5=new Label("ADRS"); l5.setBounds(30,220,45,30); l5.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l5.setAlignment(Label.CENTER); add(l5); l6=new Label("PH NO"); l6.setBounds(500,150,45,30); l6.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l6.setAlignment(Label.CENTER); add(l6); l7=new Label("OldBkDt"); l7.setBounds(30,390,55,30); l7.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l7.setAlignment(Label.CENTER); add(l7); l8=new Label("Print Date"); l8.setBounds(320,390,65,30); l8.setFont(new Font("TimesRoman",Font.PLAIN,15)); l8.setAlignment(Label.CENTER); add(l8); l9=new Label("CMemo No"); l9.setBounds(700,390,65,30); l9.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l9.setAlignment(Label.CENTER); add(l9); l10=new Label("Del Date"); l10.setBounds(550,390,55,30); l10.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l10.setAlignment(Label.CENTER); add(l10); l13=new Label("REMARKS"); l13.setBounds (30,630,85,30); l13.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l13.setAlignment (Label.CENTER); add(l13); txtCMemoNo=new TextField(); txtCMemoNo.setBounds(375,60,80,30); txtCMemoNo.setBackground(Color.white); add(txtCMemoNo); txtConsNo=new TextField(); txtConsNo.setBounds(130,60,80,30); txtConsNo.setBackground(Color.white); add(txtConsNo); txtCMemoDt=new TextField(); txtCMemoDt.setBounds(635,60,80,30); txtCMemoDt.setBackground(Color.white); add(txtCMemoDt); txtConsName=new TextField(); txtConsName.setBounds(100,150,200,30); txtConsName.setBackground(Color.white); add(txtConsName); txtAddr1=new TextField(); txtAddr1.setBounds(100,220,350,30); txtAddr1.setBackground(Color.white); add(txtAddr1); adr2=new TextField(); adr2.setBounds(100,250,350,30); adr2.setBackground(Color.white); add(adr2); adr3=new TextField(); adr3.setBounds(100,280,350,30); adr3.setBackground(Color.white); add(adr3); txtPhNo=new TextField(); txtPhNo.setBounds(570,150,150,30); txtPhNo.setBackground(Color.white); add(txtPhNo); txtBookDtold=new TextField(); txtBookDtold.setBounds(30,440,60,30); txtBookDtold.setBackground(Color.white); add(txtBookDtold); txtPrintDt=new TextField(); txtPrintDt.setBounds(320,440,60,30); txtPrintDt.setBackground(Color.white); add(txtPrintDt); txtOldCMemNo=new TextField(); txtOldCMemNo.setBounds(700,440,60,30); txtOldCMemNo.setBackground(Color.white); add(txtOldCMemNo); txtOldDlryDt=new TextField(); txtOldDlryDt.setBounds(550,440,60,30); txtOldDlryDt.setBackground(Color.white); add(txtOldDlryDt); rmrk=new TextField(); rmrk.setBounds(140,630,600,30); rmrk.setBackground(Color.white); add(rmrk); exit=new Button("EXIT"); exit.setBackground(; exit.setBounds(760,700,40,40); exit.addActionListener(this); add(exit); save=new Button("SAVE"); save.setBackground(; save.setBounds(715,700,40,40); save.addActionListener(this); add(save); next=new Button("NEXT"); next.setBackground(; next.setBounds(90,700,40,40); next.addActionListener(this); add(next); top=new Button("TOP"); top.setBackground(; top.setBounds(0,700,40,40); top.addActionListener(this); add(top); prev=new Button("PREV"); prev.setBackground(; prev.setBounds(45,700,40,40); prev.addActionListener(this); add(prev); botm=new Button("BOTM"); botm.setBackground (; botm.setBounds (135,700,40,40); botm.addActionListener (this); add(botm); ad=new Button("ADD"); ad.setBackground (; ad.setBounds (300,700,40,40); ad.addActionListener (this); add(ad); show=new Button("SHOW"); show.setBackground (; show.setBounds (345,700,40,40); show.addActionListener (this); add(show); } public void actionPerformed(ActionEvent e) { if(e.getSource()==exit) { this.dispose(); System.exit(0); } /*if(e.getSource()==save) { try { Connection con=DriverManager.getConnection("jdbc:odbc:Agency"); PreparedStatement pst=con.prepareStatement("INSERT INTO NewCon values (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)"); pst.setInt (1,Integer.parseInt(txtConsNo.getText())); pst.setInt (2,Integer.parseInt(txtCMemoNo.getText())); pst.setString (3,txtCMemoDt.getText()); pst.setString (4,txtConsName.getText()); pst.setInt(5,Integer.parseInt (txtPhNo.getText())); pst.setString(6,txtAddr1.getText()); pst.setString(7,adr2.getText()); pst.setString(8,adr3.getText()); pst.setInt(9,Integer.parseInt (txtBookDtold.getText())); pst.setInt(10,Integer.parseInt (txtPrintDt.getText())); pst.setInt(11,Integer.parseInt (txtOldDlryDt.getText())); pst.setInt(12,Integer.parseInt (txtCMemoNo.getText())); pst.setInt(13,Integer.parseInt (tot.getText())); pst.setInt(14,Integer.parseInt (stnry.getText())); pst.setString(15,rmrk.getText()); pst.executeUpdate (); con.close(); } catch(Exception e2) {System.out.println(e2);} //cs(txtConsName.getText (),txtAddr1.getText()); }*/ if(e.getSource()==ad) { try { txtCMemoNo.setText(""); txtCMemoDt.setText(""); txtConsName.setText(""); txtAddr1.setText(""); txtPhNo.setText(""); txtBookDtold.setText(""); txtPrintDt.setText(""); //txtCMemoNo.setText(""); txtOldDlryDt.setText(""); adr2.setText(""); adr3.setText(""); tot.setText(""); //stnry.setText(""); //rmrk.setText(""); Connection con1=DriverManager.getConnection("jdbc:odbc:Agency"); Statement stmt1=con1.createStatement(); ResultSet rs1=stmt1.executeQuery("SELECT Max(Cons_No) FROM NewCon"); int nextcono = rs1.getInt ("Cons_No"); System.out.println (nextcono); nextcono=nextcono+1; txtConsNo.setText ("nextcono"); con1.close(); } catch(Exception e4){} } } } 910
I have a file which contains so many lines and variable number of lines are treated as a record. For example *first ooooo xxxxx ttttt mmmm vvvvvvv *end uuu bbbb *first kkkkvvvvvv nnnn mmmmm kkkkk fffff gggg ffff kkkk lllll *end. Here the lines from *first to *end are treated as a record. The number of lines between *first and *end is not same for all the records. Suppose there are 100 records (or number of records are not predefined)like the format given in the above example. Now the entire file needs to split into two files, first having 40 and remaining in the second file. Can we split using sort utility? If possible then what is the sort card? 656
find level of following tree (state, parent) " J,D I,D H,C E,B F,B G,C B,A D,A C,A A,& K,E L,E L,F M,F N,G O,H P,I P,H Q,I R,J S,K U,P T,L 642
exception org.apache.jasper.JasperException: java.lang.NullPointerException org.apache.jasper.servlet.JspServletWrapper.handleJs pException( org.apache.jasper.servlet.JspServletWrapper.service( org.apache.jasper.servlet.JspServlet.serviceJspFile( org.apache.jasper.servlet.JspServlet.service(JspServ javax.servlet.http.HttpServlet.service(HttpServlet.j ava:717) root cause java.lang.NullPointerException org.apache.struts.taglib.TagUtils.retrieveMessageRes ources( org.apache.struts.taglib.TagUtils.message(TagUtils.j ava:1038) org.apache.struts.taglib.bean.MessageTag.doStartTag( org.apache.jsp.register_jsp._jspx_meth_bean_005fmess age_005f0( org.apache.jsp.register_jsp._jspService(register_jsp .java:94) org.apache.jasper.runtime.HttpJspBase.service(HttpJs javax.servlet.http.HttpServlet.service(HttpServlet.j ava:717) org.apache.jasper.servlet.JspServletWrapper.service( org.apache.jasper.servlet.JspServlet.serviceJspFile( org.apache.jasper.servlet.JspServlet.service(JspServ javax.servlet.http.HttpServlet.service(HttpServlet.j ava:717) 1465
Write a function which accepts list of nouns as input parameter and return the same list in the plural form. Conditions: i) if last letter is r then append s ii) if word ends with y then replace it by ies iii) call this function in main() and produce the required output. for eg:- if chair is input it should give chairs as output. 2495
how to test pierrot divisor 900
Dear sirs, Hi, I would like to inform you that I want to perform a project using MLP neural network to recognize binary images containing three types of geometric shapes such as squares,rectangels and circles. Furthermore,each image includes only one geometric type. The output of network would be: '1' if the network detects square shape. '2' if the network detects rectangle shape. '3' if the network detects circle shape. '4' if none of these shapes detected. Would you please send me a matlab source code for this project? Your prompt reply would be so appreciated. regards, 675
Code for Two Classes for Doing Gzip in Memory? 1185
How to Check if Folder Exists? 89
Hello Sir, Thanks for the Solution but, can you pls. Explain the coding for the Static Function & static variable from the below coding....waiting for Ans. class fact { public static void Main() { fact f=new fact(); int x=1; //Declaration of x as 1 int k=Convert.ToInt32(Console.ReadLine()); for(int i=1;i<=k;i++) { x= x *i; } System.Console.WriteLine(x); } } 831
find out the list of users who have access to all t-codes starts with 'SU'? thanks in advance all. 618
Code for Presenting Parent/Child Data in a Data Grid Row? 960
Financial: credit card number validation) Credit card numbers follow certain patterns. A credit card number must have between 13 and 16 digits. It must start with: &#9632; 4 for Visa cards &#9632; 5 for Master cards &#9632; 37 for American Express cards &#9632; 6 for Discover cards In 1954, Hans Luhn of IBM proposed an algorithm for validating credit card numbers. The algorithm is useful to determine whether a card number is entered correctly or whether a credit card is scanned correctly by a scanner. All credit card numbers are generated following this validity check, commonly known as the Luhn check or the Mod 10 check, which can be described as follows (for illustration, consider the card number 4388576018402626): 1. Double every second digit from right to left. If doubling of a digit results in a two-digit number, add up the two digits to get a single-digit number. 2 * 2 = 4 2 * 2 = 4 4 * 2 = 8 1 * 2 = 2 6 * 2 = 12 (1 + 2 = 3) 5 * 2 = 10 (1 + 0 = 1) 8 * 2 = 16 (1 + 6 = 7) 4 * 2 = 8 2. Now add all single-digit numbers from Step 1. 4 + 4 + 8 + 2 + 3 + 1 + 7 + 8 = 37 3. Add all digits in the odd places from right to left in the card number. 6 + 6 + 0 + 8 + 0 + 7 + 8 + 3 = 38 4. Sum the results from Step 2 and Step 3. 37 + 38 = 75 5. If the result from Step 4 is divisible by 10, the card number is valid; otherwise, it is invalid. For example, the number 4388576018402626 is invalid, but the number 4388576018410707 is valid. Write a program that prompts the user to enter a credit card number as a long integer. Display whether the number is valid or invalid. Design your program to use the following methods: /** Return true if the card number is valid */ public static boolean isValid(long number) /** Get the result from Step 2 */ public static int sumOfDoubleEvenPlace(long number) /** Return this number if it is a single digit, otherwise, return * the sum of the two digits */ public static int getDigit(int number) /** Return sum of odd place digits in number */ public static int sumOfOddPlace(long number) /** Return true if the digit d is a prefix for number */ public static boolean prefixMatched(long number, int d) /** Return the number of digits in d */ public static int getSize(long d) /** Return the first k number of digits from number. If the * number of digits in number is less than k, return 2543
Common UI for Multiple web applications. Suppose there are 35 websites using same third party controls.These 3rd party controls are made together that all 35 websites can use these controls.If we put all 3rd party controls and use its dll in 35 websites,only class files will be accessable. But I want to use CSS,images also in all 35 websites. how I can design the N-tier solution for this project. 1012
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