Substitute digits for the letters to make the following
subtraction problem true.
S A N T A
- C L A U S
-----------------
X M A S
Note that the leftmost letter can't be zero in any word.
Also, there must be a one-to-one mapping between digits and
letters. e.g. if you substitute 3 for the letter M, no other
letter can be 3 and all other M in the puzzle must be 3.
Answer / guest
One of the simplest brain teaser as there are total 26
possible answers.
It is obvious that S=C+1. Since A-S=S, it is clear that
A=2*S or 2*s-10. Also, L and X are interchangeable.
SANTA - CLAUS = XMAS
24034 - 16492 = 7542
24034 - 17492 = 6542
24074 - 15432 = 8642
24074 - 18432 = 5642
24534 - 16492 = 8042
24534 - 18492 = 6042
24794 - 16452 = 8342
24794 - 18452 = 6342
24804 - 15462 = 9342
24804 - 19462 = 5342
24974 - 16432 = 8542
24974 - 18432 = 6542
36806 - 27643 = 9163
36806 - 29643 = 7163
36156 - 27693 = 8463
36156 - 28693 = 7463
62132 - 54206 = 7926
62132 - 57206 = 4926
62172 - 53246 = 8926
62172 - 58246 = 3926
62402 - 53276 = 9126
62402 - 59276 = 3126
62712 - 53286 = 9426
62712 - 59286 = 3426
62932 - 58206 = 4726
62932 - 54206 = 8726
Is This Answer Correct ? | 1 Yes | 1 No |
Substitute digits for the letters to make the following subtraction problem true. S A N T A - C L A U S ----------------- X M A S Note that the leftmost letter can't be zero in any word. Also, there must be a one-to-one mapping between digits and letters. e.g. if you substitute 3 for the letter M, no other letter can be 3 and all other M in the puzzle must be 3.
A 3 digit number is such that it's unit digit is equal to the product of the other two digits which are prime. Also, the difference between it's reverse and itself is 396. What is the sum of the three digits?
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