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1. Write a c pgm to print 1 to 100 without using loops.
2. Write a c pgm for leap year
3. Write a c pgm fibbonacci series,factorial
4. Write a c pgm count no of lines , blanks, tabs in a
para(File concept)
5. Write a c pgm to print the letter as per given condition
i.e.. if u give 4
out put should b
4 4 4 4
4 4 4 4
4 4 4 4
4 4 4 4
6.how do get the o/p in number from 1 to 100 in the screen
without using control statement?
7. who do u print the word "hello world" without using
"printf" statement?
8. write sql program to get the detail of student in a
class?
Definitions:
structure
union
arrays
linkedlist
macros
directives
difference b/w
pre processorsDiffrence:
1.Constructors and destructors
2.Structure and Union
3.Array and Lists
4.pre processor...
5. Privillages in C++
6.structure and union
7.break and continue
8.while and dowhile Pgm..
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Answer / vignesh1988i
1) 1 -100 without looping....
#include<stdio.h>
#include<conio.h>
int i=1;
void main()
{
i<=100 ? printf("%d\n",i) : getch(); //conditional operator
i++;
main(); //recursive calling of main() function
}
7) printing a string without printf()
#include<stdio.h>
#include<conio.h>
void main()
{
if(printf("hello world"))
getch();
}
5) printing ur sequence
#include<stdio.h>
#include<conio.h>
void main()
{
int m;
printf("enter ur number:");
scanf("%d",&m);
for(int i=1;i<=m;i++)
{
for(int j=1;j<=m;j++)
printf("%d ",m);
printf("\n");
}
getch();
}
6) printing 1-100 without using loops as well as control statement...
same answer which i have made for your QUESTON 1... and conditional operator is not a control statement...
3) a) very basic and simple logic fabbonacci series:
#include<stdio.h>
#include<conio.h>
void main()
{
int a=1,b=-1,c,n;
printf("enter the no. of terms :");
scanf("%d",&n);
for(int i=1;i<=m;i++)
{
c=a+b;
printf("%d\n",c);
b=a;
a=c;
}
getch();
}
b) Factorial :
#include<stdio.h>
#include<conio.h>
void main()
{
int m,j=1;
printf("enter ur number :");
scanf("%d",&m);
for(int i=1;i<=m;i++)
j=j*i;
printf("the factorial is : j");
getch();
}
remaining i ll answer today evening....
thank u
| Is This Answer Correct ? | 39 Yes | 13 No |
Answer / antony btitto
8:ANSWER
#include<stdio.h>
#include<conio.h>
void main()
{
int i=0,n;
printf(“enter the n value:);
scanf(“%d”,&n);
while(n>i)
{
printf(“this is while condition programe”);
}
getch();
}
| Is This Answer Correct ? | 10 Yes | 5 No |
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C 
