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Tic-Tac-Toe is being played. One 'X' has been placed in one
of the corners. No 'O' has been

placed yet.

Where does the player that is playing 'O' has to put his
first 'O' so that 'X' doesn't win?

Assume that both players are very intelligent. Explain your
answer

Answers were Sorted based on User's Feedback



Tic-Tac-Toe is being played. One 'X' has been placed in one of the corners. No 'O�..

Answer / guest

"O" should be placed in the center.

Let's number the positions as:

1 | 2 | 3

---------

4 | 5 | 6

---------

7 | 8 | 9

It is given that "X" is placed in one of the corner
position. Let's assume that its at position 1.

Now, let's take each position one by one.

? If "O" is placed in position 2, "X" can always win by
choosing position 4, 5 or 7.

? If "O" is placed in position 3, "X" can always win by
choosing position 4, 7 or 9.

? If "O" is placed in position 4, "X" can always win by
choosing position 2, 3 or 5.

? If "O" is placed in position 6, "X" can always win by
choosing position 3, 5 or 7.

? If "O" is placed in position 7, "X" can always win by
choosing position 2, 3 or 9.

? If "O" is placed in position 8, "X" can always win by
choosing position 3, 5 or 7.

? If "O" is placed in position 9, "X" can always win by
choosing position 3, or 7.

If "O" is placed in position 5 i.e. center position, "X"
can't win unless "O" does something foolish ;))

Hence, "O" should be placed in the center.

Is This Answer Correct ?    5 Yes 1 No

Tic-Tac-Toe is being played. One 'X' has been placed in one of the corners. No 'O�..

Answer / ni hao

If what answer #1 said is true, it would end in a cat's
game (tie) unless "X" does something foolish, which he
wouldn't considering that both players are very
intelligent..

Is This Answer Correct ?    0 Yes 0 No

Post New Answer

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