There are 3 persons X, Y and Z. On some day, X lent
tractors to Y and Z as many as they had. After a month Y
gave as many tractors to X and Z as many as they have.
After a month Z did the same thing. At the end of this
transaction each one of them had 24.
Find the tractors each originally had?
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Answer / guest
One way to solve it is by making 3 equations and solve them
simultaneously. But there is rather easier way to solve it
using Backtracing.
It's given that at the end, each had 24 tractors (24, 24,
24) i.e. after Z gave tractors to X & Y as many as they
had. It means that after getting tractors from Z their
tractors got doubled. So before Z gave them tractors, they
had 12 tractors each and Z had 48 tractors. (12, 12, 48)
Similarly, before Y gave tractors to X & Z, they had 6 & 24
tractors respectively and Y had 42 tractors i.e. (6, 42,
24)
Again, before X gave tractors to Y & Z, they had 21 & 12
tractors respectively and X had 39 tractors i.e. (39, 21,
12)
Hence, initially X had 39 tractors, Y had 21 tractors and Z
had 12 tractors.
| Is This Answer Correct ? | 10 Yes | 0 No |
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