Answer / ventola

Divide 8 balls in 3 groups (3,3,2)
(weigh 1st) the first set (a=3, b=3) if a is less then take
randomly pick 2 balls from set 'a' and weigh them (2nd time)
again. if they are equal then the odd man out is the one
with less weight or the less side is the one.

if sets a & b are equal then weigh set c (=2)

Answer / madhavi

hiee im madhavi

put all the balls in a bucket n pour water
the lighter ball floats on top
that ball will be lightest ball than all

:):) be smart n work on guys:):)

Answer / suresh cn

Depending on the type of weighing scale ie
balance/spring/platform/indicative, I will use methods as
applicable for easy determination.

Answer / juned

1> first make two groups of balls (each contains 4)then
weigth them.

2> seprate the ligther one and then again grouped them into
two (each contains 2)then weigth them.

3> again seprate the liether one
and at last weigth the remaining two and identify the
ligther one

Answer / shrikant

people...
listen
this is the case of optimisation....
if u take 4 balls set then u end up in 3 tries...
if u take 3 3 2 set...
then try and see
frst weight 3..3
u no the unbalanced one...
select that set and put any two random balls in both pans...
if equal the ball not put in is the ball of concern...
else we are left with the other set...
that can be done easily..
2 balls each in one pan...
thats it

Answer / t mahesh

take 6 balls out of 8 balls .. .
weight 3 and 3 balls
if they are equal remaining two balls one ball is weightless
then weight that two balls to findout weightless ball

else one of that 3 balls one ball is wieghtless
take 2 balls from those 3 balls and wight that one if both
are equal remaining ball is weightless..

Answer / raghav_tantry

calculate the avg weight then see which balls weight is less
,,

Answer / vishnu

i will throw all balls down one after other.the ball which
weights less it will bouns more than other balls.

"TILL NOW I DID'NT SEE WEIGHTSCALE"

Answer / shravan

to each pan on the weigh balance...keep four balls & the
set that has less weight has to be seperated in to 2 sets
of two each & then the same measurement is taken to find
the set with less weight. Then select the light weight set
& use each ball in weigh balance pans & the ball with less
weight is the Odd Ball

Answer / shree

PEOPLE ..WE ARE NOT OPTIMIZING ON THE SOLUTION!!
WE NEED TO HAVE A SET OF 2 EACH ...I.E 2*4 GROUPS
THEN WEIGH ANY SETS .. IF U GET THE ODD BALL IN THE FIRST
WEIGHING , U MAY SIMPLY REJECT THE REMAININ 4 BALLS AND
LATER U MAY PROCEED AS DISCUSSED ABOVE..ELSE IF NOT IN FRST
ATTEMPT U MAY PROCEED ..AS THE CONVENTION AND STILL GET A
MAX OF 3 WEIGHING REQUIRED

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