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what is the output of the following code?
main()
{
int I;
I=0x10+010+10;
printf("x=%x",I);
}
give detailed reason
- 3 Answers
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Answer / yogesh bansal
Output of this program is 22
reason is :
0x10 is hexadecimal value which is equal to 16 in decimal.
010 is octal value which is equal to 8 in decimal
10 is decimal value
so total is 16+8+10= 34
I value is 34.
Now we are printing the value of I on hexadecimal using %x
34 is equal to 0x22 in hexadecimal.
so the output is 22 in hexadecimal
Hope its is clear to you
| Is This Answer Correct ? | 70 Yes | 8 No |
Answer / kartik
Output of this program is 22
reason is :
0x10 is hexadecimal value which is equal to 16 in decimal.
010 is octal value which is equal to 8 in decimal
10 is decimal value
so total is 16+8+10= 34
I value is 34.
Note:The person above me has given the corrst infm however the output is 34.
Try and run the program in C Compiler
| Is This Answer Correct ? | 12 Yes | 7 No |
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